Lighting a match
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Answer:
0.04658 m from the nut
Explanation:
Recall that torque is defined as the vector product of force (F) times distance (d). Then, given that the force is applied perpendicular to the wrench, gives the sine of the angle (90 degrees) equal to 1, simplifying the calculation which consists basically on solving for d in the equation:
2.25 N*m = 48.3 N * d
d = 2.25 /48.3 m ≈ 0.04658 m
Answer:
D
Explanation:
they can see this along with many other fish.
Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?
Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.
(a) What is the electric potential at point a due to q1 and q2?
(b) What is the electric potential at point b?
(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?
Answer:
a) the potential is zero at the center .
Explanation:
a) since the two equal-magnitude and oppositely charged particles are equidistant
b)(b) Electric potential at point b, v = Σ kQ/r
r = 5cm = 0.05m
k = 8.99*10^9 N·m²/C²
Q = -2 microcoulomb
v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m
v = -105 324 V
c)workdone = charge * potential
work = -6.00µC * -105324V
work = 0.632 J
Protons- 17
neutrons-20
electrons-17
