the answer for this question is c
Answer:
Noennt ied olod l qeu es ocmo a balazuna de cozcna
in
Explanation:
Responder:
Velocidad = 41.5m / s
Espacio recorrida = 352.5 metros
Explicación:
Dado lo siguiente:
Velocidad inicial (u) = 19.8 km / h
Aceleración (a) = 2.4m / s ^ 2
Tiempo de viaje (t) = 15 s
A.) velocidad después de 15 s
Velocidad inicial = (19.8 × 1000) m / 3600s Velocidad inicial = 19800m / 3600 = 5.5m / s
Usando la ecuación: v = u + at, donde v es la velocidad
v = 5.5 + 2.4 (15)
v = 5.5 + 36
v = 41.5m / s
Espacio recorrida:
v ^ 2 = u ^ 2 + 2aS; donde S es la distancia recorrida
41.5 ^ 2 = 5.5 ^ 2 + 2 × (2.4) × S
1722.25 = 30.25 + 4.8S
1722.25 - 30.25 = 4.8S
1692 = 4.8S S = 1692 / 4.8 S = 352.5m
<u>We are Given:</u>
Mass of the block (m) = 500 grams or 0.5 Kg
Initial velocity of the block (u) = 0 m/s
Distance travelled by the block (s) = 8 m
Time taken to cover 8 m (t)= 2 seconds
Acceleration of the block (a) = a m/s²
<u>Solving for the acceleration:</u>
From the seconds equation of motion:
s = ut + 1/2* (at²)
<em>replacing the variables</em>
8 = (0)(2) + 1/2(a)(2)²
8 = 2a
a = 4 m/s²
Therefore, the acceleration of the block is 4 m/s²
Answer:
1.0 x 10-14.
Explanation:
We then replace the term on the right side of this equation with a constant known as the water dissociation equilibrium constant, Kw. In pure water, at 25C, the [H3O+] and [OH-] ion concentrations are 1.0 x 10-7 M. The value of Kw at 25C is therefore
