<span><span>Big Bang- January 1
</span><span>Origin of Milky Way Galaxy- May 1
</span><span>Origin of the solar system- September 9
</span><span>Formation of the Earth- September 14
</span><span>Origin of life on Earth<span>- September 25</span></span></span>
Answer:
3m/s
Explanation:
Given parameters:
Initial speed = 2m/s
Acceleration = 0.5m/s²
Time = 2s
Unknown:
Final speed = ?
Solution:
To solve this problem, we apply the right motion equation;
V = U + at
V is the final speed
U is the initial speed
a is the acceleration
t is the time
V = 2 + (2 x 0.5)
V = 2 + 1
V = 3m/s
Explanation:
The net force of each square is the combination of the forces in each direction. The direction is the... direction the square would go in due to the net force. The magnitude of the net force is how large it is. So if you had a force pushing 2N to the left and 1N to the right, then the net force would be 1N to the left; because the two oppose eachother. If they were going in the same direction, then they'd add to each other. And perpendicular net forces (like one pushing up and another pushing left) can create net forces in diagonal directions.
I'm not going to do all of these for you because they're basically all the same thing and it's good practice for you anyway. But I'll do the first three just so you can get the idea:
1. The net force's magnitude is 4N and it's direction is to the right.
2. The net force's magnitude is 4N and it's direction is to the left.
3. The net force's magnitude is 0N and it has no direction because they are equal forces acting in opposite directions.
Explanation:
Acceleration is the change in velocity over time.
a = Δv / Δt
a = (26 m/s − 9 m/s) / 8 s
a ≈ 2.1 m/s²
The frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
<h3>What is torque?</h3>
Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
Where,
is the frictional torque
is the final angular velocity
is the initial angular velocity
is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
![\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]](https://tex.z-dn.net/?f=%5Crm%20T_f%20%5Ctheta%20%3D%5Cfrac%7B1%7D%7B2%7D%20I%20%5B%5Comega%5E2-%5Comega_0%5E2%5D)
To learn more about the torque, refer to the link;
brainly.com/question/6855614
#SPJ1