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3 years ago

9

Designing buildings to maximize absorption of sunlight during winter and to keep the interiors cool during summer is referred to

as ________. geothermal energy collection nuclear energy collection active solar energy collection passive solar energy collection wind energy collection

1 answer:

bearhunter [10]3 years ago

8 0

The answer to this question is Passive Solar Energy Collection. Passive Solar Energy Collection is a building design where in parts of the building like windows, walls, absorbs sunlight during winter and the interiors of the building are cool during summer time. In this design, the cost of having this building may be costy.

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A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the

Rama09 [41]

1) $1.11\cdot 10^{-7} J$

The capacitance of a parallel-plate capacitor is given by:

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

$r=\frac{2.0 cm}{2}=1.0 cm=0.01 m$

so the area is

$A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2$

While the separation between the plates is

$d=0.50 mm=5\cdot 10^{-4} m$

So the capacitance is

$C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F$

And now we can find the energy stored,which is given by:

$U=\frac{1}{2}CV^2=\frac{1}{2}(5.56\cdot 10^{-12} F/m)(200 V)^2=1.11\cdot 10^{-7} J$

2) 0.71 J/m^3

The magnitude of the electric field is given by

$E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m$

and the energy density of the electric field is given by

$u=\frac{1}{2}\epsilon_0 E^2$

and using

$E=4\cdot 10^5 V/m$ , we find

$u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3$

7 0

4 years ago

Which of the following planets has the strongest winds in the solar system?

Solnce55 [7]

Jupiter does. :) it has many storms, causing the wind

6 0

3 years ago

Read 2 more answers

How and why does breathing rate increase during exercise

kondor19780726 [428]

<span>Your heart speeds up to pump extra food and oxygen to the muscles. Breathing speeds up to get more oxygen and to get rid of more carbon dioxide. When a fit person, such as an athlete, exercises the pulse rate, breathing rate and lactic acid levels rise much less than they do in an unfit person.
</span>

7 0

4 years ago

I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b

viva [34]

Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, $P=hg\rho$

Where h is the height that water is to reach, g is gravitational constant and $\rho$ is the density, in this case, we assume $\rho$ of pure water as $1000 Kg/m^3$

Assuming $g=10 m/s^{2}$

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

$P=0.5v^{2}\rho$ where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

$P=0.5v^{2}\rho=hg\rho$

Notice that $\rho$ is common hence

$0.5v^{2}=hg$

Making V the subject of the formula

$v^{2}=2hg$

$v=\sqrt 2hg$

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

$v=\sqrt 2*10*6.4=11.3137085 m/s$

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

$v=\sqrt 2hg$

Taking g as 9.8 and h now is 8m

$v=\sqrt 2*8*9.8$

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

6 0

3 years ago

A ball moves along a smooth metal surface while an identical ball moves along concrete.

mojhsa [17]

Answer:

2. The metal surface exerts less frictional force because there are fewer bumps and irregularities on it than there are on the concrete.

Explanation:

Frictional force is a force that is exerted between two surfaces in contact with each other. Frictional force always opposes the direction of relative motion of the two surfaces: for instance, for a ball moving along a surface, the force of friction exerted by the surface on the ball points opposite to the direction of motion of the ball.

The magnitude of the frictional force for a ball moving on a flat surface is given by

$F=\mu mg$

where

$\mu$ is the coefficient of friction

m is the mass of the ball

g is the acceleration of gravity

The value of $\mu$ depends on the type of surface involved. In particular, a smooth surface has a smaller value of $\mu$ , while a rough surface will have a bigger value. In this case, we are comparing a smooth metal surface with concrete: since the metal surface has fewer bumps and irregularities than concrete, it has a smaller value of coefficient of friction, so it exerts less frictional force than concrete.

3 0

3 years ago