Answer is 10N to the left
To find the resultant resultant force, subtract the largest force (35N to the left) by the smallest force (25N to the right).
35 – 25 = 10N
It would be 10N to the left because the force exerted to the left is larger than the force exerted to the right.
Answer:
x = 16 [m]
Explanation:
This problem can be solved using the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 5 [m/s]
a = acceleration = 3 [m/s²]
t = time = 2 [s]
Now we can find the displacement using the following equation of kinematics.
Gravity always produces a pair of forces ... two of them.
The forces are opposite.
One force pulls 'A' toward 'B'.
The other force pulls 'B' toward 'A'.
For this question, let's say Astronaut Bob is standing on Mars.
There are two forces of gravity between the Astronaut and the planet.
One force pulls Bob toward Mars.
The other force pulls Mars toward Bob.
The force that pulls Bob toward Mars is what we call his "weight".
The other force ... the one that pulls Mars toward Bob ... is
the force that nobody ever talks about, but it's there.
The force that attracts you toward the Earth is
your "weight" on Earth.
The force that attracts the Earth toward you is
the Earth's weight on you.
The two forces are equal !
Answer:
Approximately and approximately .
Explanation:
Let and denote the capacitance of these two capacitors.
When these two capacitors are connected in parallel, the combined capacitance will be the sum of and . (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)
.
On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:
.
(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field () between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored stays the same.)
The question states that:
- , and
- .
Let the capacitance of these two capacitors be and . The two equations will become:
.
From the first equation:
.
Hence, the in the second equation here can be replaced with . That equation would then become:
.
Solve for :
.
.
.
Solve this quadratic equation for :
or .
Substitute back into the equation for :
In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately and approximately (both values are rounded to two significant digits.)