A solution was made by mixing 60.5 g of glucose (C6H12O6) with enough water to make 325 ml of solution. What is the percent (mas

Question

3 years ago

15

s-volume) concentration of the solution and the molarity of the solution

1 answer:

IgorC [24] · Answer 1 · 2022-02-15T13:58:58+03:00

mass percent concentration = 15.7 %

molar concentration of glucose solution 1.03 M

Explanation:

To calculate the mass percent concentration of the solution we use the following formula:

concentration = (solute mass / solution mass) × 100

solute mass = 60.5 g

solution mass = solute mass + water mass

solution mass = 60.5 + 325 = 385.5 g (I used the assumption that the solution have a density of 1 g/mL)

concentration = (60.5 / 385.5) × 100 = 15.7 %

Now to calculate the molar concentration (molarity) of the solution we use the following formula:

molar concentration = number of moles / volume (L)

number of moles = mass / molecular weight

number of moles of glucose = 60.5 / 180 = 0.336 moles

molar concentration of glucose solution = 0.336 / 0.325 = 1.03 M

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