1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
g100num [7]
3 years ago
8

grandma baked cookies. she gave 7 to sandy. she gave half of what were left, plus one to sue. she gave 3 to stan. then she gave

half of what were left to steve. since there were only two cookies left, she ate them herself. how many cookies did she bake?
Chemistry
1 answer:
scoray [572]3 years ago
8 0
I believe your answer is 23.
Credit: answers.yahoo.com

Hope this helps!
You might be interested in
Every conversion factor is a ratio that is<br> equal to 1<br> less than 1<br> greater than 1
miss Akunina [59]

equal to 1

Explanation:

All conversion factors used in any calculation is usually a ratio that is equal to 1. This is because when 1 is used to multiply or divide any number, the number stays the same.

  • Conversion factors are useful in making the simplification of an expression very simple. They are usually ratios of 1.
  • It follows that a conversion factor is a number that when multiplied or divided by itself will stay the same.

Learn more:

conversion factor: brainly.com/question/555814

#learnwithBrainly

4 0
3 years ago
How do the atmosphere conditions near the beginning of Precambrian time contrast with the atmosphere conditions that are present
babunello [35]
The early precambrian atmosphere consisted primarily of nitrogen and carbon dioxide with almost no oxygen. 

<span>Today, the atmosphere contains about 20% oxygen, less carbon dioxide and similar amounts of nitrogen. </span>

<span>Photosynthetic green-leaf plants and trees are largely responsible for the change, converting carbon dioxide to oxygen.</span>
5 0
3 years ago
6 C(s) + 3 H2(g) → 2 C6H6(l) Δ H = 49 kJ<br><br> TRUE or FALSE
VMariaS [17]

Answer:

True => ΔH°f for C₆H₆ = 49 Kj/mole

Explanation:

See Thermodynamic Properties Table in appendix of most college level general chemistry texts. The values shown are for the standard heat of formation of substances at 25°C. The Standard Heat of Formation of a substance - by definition - is the amount of heat energy gained or lost on formation of the substance from its basic elements in their standard state. C₆H₆(l) is formed from Carbon and Hydrogen in their basic standard states. All elements in their basic standard states have ΔH°f values equal to zero Kj/mole.

7 0
3 years ago
PLS HELP!!! ASAP
mina [271]

Answer: The answer is Fossil A is younger than the index fossil.

Explanation: Because it’s the newest layer

7 0
3 years ago
These are elements that
agasfer [191]

Answer:

metals are those element that have luster,malleable, ductile good conductors of heat and électricity, must have high melting and boiling points, and lose electrons in chemical reactions.

6 0
2 years ago
Other questions:
  • The half-life for the radioactive decay of C-14C-14 is 5730 years. You may want to reference (Pages 598 - 605) Section 14.5 whil
    7·1 answer
  • what would the percentage of thorium-232 ( parent compound) be in a rock that was dated at 1.8 billion years
    14·1 answer
  • Consider a reaction in which hydrogen (H2) and oxygen (O2) react to form water (H2O). By mass, the mixture of reactants is 1 par
    7·1 answer
  • Iron, a metal, has which of the following features?
    5·1 answer
  • Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide. A) Mg + AlO → MgO + Al
    11·2 answers
  • Why does water work bad with oil? Explain
    7·2 answers
  • How is science based on observation used as evidence? How can this evidence be used?
    10·2 answers
  • What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
    11·1 answer
  • Hiiiiiiiiiiii peopleeeee
    11·2 answers
  • HCl + Fe + ____ + H²
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!