Explanation:
because there are 4 Iodines on the left, we'll put. 4 in front of NaI to balance it. This would result in 4 Na on the left, so we'll put a 2 in front of Sodium Sulfate to balance the right side. Now we have 4 Na and I on both side, as well as 2 Sulfate on both sides. Pb is already balanced. The equation is now complete.
25/2 and 96/X
CROSS MULTIPLY.
2x=2,400.
divide by 2.
x=1,200.
you take the GIVEN MASS of an element, and you put it on top, the coefficient is what it’s over. i believe this is right
Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
Answer: -
Thus ¹³C ⁻ ion has 7 electrons, 7 neutrons and 6 protons.
Explanation: -
The mass number for ¹³C = 13
The atomic number for ¹³C = 6
Number of electrons present in ¹³C = atomic number = 6
Number of protons present in ¹³C = atomic number = 6
Number of neutrons present in ¹³C = mass number - atomic number = 13 - 6 = 7
For ¹³C ⁻ ion,
Number of electrons present = 6 + 1 = 7
Thus ¹³C ⁻ ion has 7 electrons, 7 neutrons and 6 protons.
Answer:
B. saturated.
Explanation:
The important point here is 'at a given temperature'. The amount of solute it can hold will vary according to the temperature.