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tekilochka [14]
3 years ago
6

Which describes mid-oceanic ridges?

Chemistry
1 answer:
Strike441 [17]3 years ago
8 0
C. Mid-ocean ridges are constantly pulling apart and are in the ocean.
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How do emulsifiers help oil and water to mix and not separate?
Olin [163]

Answer:

To prevent the mixture from separating substances called emulsifiers can be added. These help to form and stabilise the emulsions, preventing or slowing the water and fat/oil from separating. ... The hydrophilic end of the emulsifier molecule is attracted to the water and the hydrophobic end is attracted to the fat/oil.

3 0
3 years ago
oxygen is a common oxidizing agent in nature. what change in the oxidation number of oxygen must occur if it is to be an oxidizi
Minchanka [31]

Answer is: the oxidation number of oxygen must decrease.

Oxidizing agent is element (substance) that gain electrons in chemical reaction.

For example, balanced chemical reaction: C + O₂ → CO₂.

Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)

6 0
3 years ago
How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
strojnjashka [21]
2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!
8 0
4 years ago
An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi
arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

             r = \frac{mv}{qB}

where,   m = mass,      v = velocity

              q = charge,    B = magnetic field

Therefore, q will be calculated as follows.

         q = \frac{mv}{rB}

            = \frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}

            = \frac{34.98 \times 10^{-22}}{0.01092}

            = 3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}

            = +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0
3 years ago
Equilibrium reaction chromate
qaws [65]
Could you further explain what you are asking
8 0
3 years ago
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