Answer:
Captive breeding
Explanation:
Endangered species, such as the Black Rhino, Saola, Cross River Gorrillas, the Blue Whale, and a host of others, are species that are critically under the verge of extinction either as a result of the destruction of their habitat or poaching/overhunting, which has really led to steep decline in their population.
Several attempts have been made and ate being made to ensure the preserve and protect these endangered species form going extinct.
However, the best of such measures or practices is arguably referred to as Captive Breeding.
Captive breeding involves the capturing of some of these endangered species and transporting them to enclosed and monitored facilities such as zoos in other to promote the increase preservation and survival of these species and ensuring they don't go extinct.
In most cases, when a considerable increase in population in these facilities is established through breeding, some of them are later on reintroduced to their natural habitat in the wild. This do not only ensure biodiversity, it also ensures the population of the endangered species to grow and avoid such species from going extinct.
Answer: 25.5°C
Explanation: take the average of the reading i.e (25 + 26)/2= 25.5
<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.
<u>Explanation:</u>
All radioactive decay processes undergoes first order reaction.
To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:
![k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%20%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken = 1.52 hrs
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= Initial concentration of reactant = 100 g
[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g
Putting values in above equation, we get:
To calculate the half life period of first order reaction, we use the equation:
where,
= half life period of first order reaction = ?
k = rate constant = 
Putting values in above equation, we get:
Hence, the half life of the sample of silver-112 is 3.303 hours.
Answer:
The products are: KCl03 and H20.
Explanation:
The reaction between HC03 (chloric acid) and KOH (potassium hydroxide) is:
HC03 + KOH ----> KCl03 (KCl03 and H20) + H20 (water)
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<em>The reaction is of the double displacement type (in this case parts of the reagents are exchanged, producing two generating new compounds).</em>
