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melomori [17]
3 years ago
9

In the following diagram line C intersects line D. Using complete sentences, classify the relationship between <7 and <8 c

reated by the intersection of lines C and D. Use complete sentences to explain how the special angles created by the intersection of lines C and D can be used to solve for y. Solve for y and find the measures of <7 and <8.
Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

sorry wish i knew to need the answer also

Step-by-step explanation:

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FrozenT [24]

Answer:

(-2,\, 0).

Step-by-step explanation:

Dilate a point (x,\, y) by a scale factor of r with (a,\, b) as the center, and the resultant point would be at (a + r\, (x - a),\, b + r\, (y - a)).

In this question:

Point to dilate: (x,\, y) = (-8,\, 0).

Scale factor: r = 0.25.

Center of dilation: (a,\, b) = (0,\, 0).

The resultant point would be:

(0 + 0.25\, (-8 - 0),\, 0 + 0.25\, (0 - 0)), which simplifies to (-2,\, 0).

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3 years ago
What is the slope for -4x-3y=6
loris [4]

Answer: y=4/3x+2


Step-by-step explanation:

-4x-3y=6

+4x       +4x

-3y=4x+6

-3/-3=4/3+6/3

y=4/3x+2


7 0
3 years ago
A radioactive substance is decaying exponentially. If there are initially 15 grams of the substance and after 3 hours there are
sukhopar [10]

Answer:

Ok, an exponential decay is written as:

P(t) = A*(1 - r)^t

Where A is the initial population, r is the rate of decay and t is the unit of time.

We know that the initial population is 15g

then:

P(t) = 15g*(1 - r)^t

And at t = 3hs, the populations is 5g

P(5h) = 5g = 15g*(1 - r)^5

5/15 = 1/3 = (1 - r)^5

(1/3)^(1/5) = (1 - r) = 0.8

Now, the half life time of the sustance is t = x, such that the population reduces to it's half:

P(x) = A/2 = 15g/2 = 7.5g

Then:

7.5g = 15g*0.8^x

7.5g/15g = 1/2 = 0.8^x

Now, remember that if we have:

a = b^x

then

x = ln(a)/ln(b)

ln(1/2)/ln(0.8) = x = 3,11 hours

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3 years ago
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Mrac [35]

Answer:

F(x)= -19

Step-by-step explanation:

Just plug in ‘-3’ for every ‘x’ in the equation.

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8 0
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Answer:

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