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3 years ago

What fractions are equivalent to - 2/3

Mathematics

2 answers:

Valentin [98]3 years ago

5 0

Answer:

- 4/6, -6/9, -8/12, -10/15, -12/18, -14/21, and more

Slav-nsk [51]3 years ago

4 0

Answer:

-4/6, -6/9, -8/12

Step-by-step explanation:

All you're doing is multiplying each side, like for -4/6, you multiply -2 by 2 and multiply 3 by 2 to get -4/6. Remember whatever you do to one side you must do to the other

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In a box of 25 switches, 3 are defective. what is the probability of randomly selecting a switch that is not defective? enter yo

sergey [27]

Not defective : 25 - 3 = 22
probability of not defective : 22/25

22/25 × 100% = 88%

5 0

3 years ago

A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in th

RideAnS [48]

Answer:

From 3 to 6 seconds, the rocket is falling 11 yards per second.

Step-by-step explanation:

Normal pace of progress is exactly the same thing as the slant. Since this is explanatory, we can't track down the specific pace of progress as we could if this were a straight capacity. Be that as it may, we can utilize a similar thought. At the point when t = 3, h(t) = 33, so the organize point is (3, 33). At the point when t = 6, h(t) = 0, so the facilitate is (6, 0). Attachment those qualities into the incline recipe:

m= 0-33/6-3 and m=-33/3 which is 11

From 3 to 6 seconds, the rocket is falling 11 yards each second.

Brainliest?

7 0

2 years ago

The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 73 minutes and a standard devi

Vesnalui [34]

Answer:

(a) $X\sim N(\mu = 73, \sigma = 16)$

(b) 0.7910

(d) 0.6464

Step-by-step explanation:

Let X = amount of time that people spend at Grover Hot Springs.

The random variable X is normally distributed with a mean of 73 minutes and a standard deviation of 16 minutes.

(a)

The distribution of the random variable X is:

$X\sim N(\mu = 73, \sigma = 16)$

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

$P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

$P(X$

*Use a z-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

$P(60$

*Use a z-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

6 0

3 years ago

BRAINLIEST to correct answer!!

Len [333]

They are equally spaced so all the circles share the same center point.

4 0

2 years ago

Read 2 more answers

Fran has a monthly income of $2940, and budgets 9% of that amount for groceries.

notsponge [240]

Answer: $265

Step-by-step explanation: Fran has a monthly income of $2940, and she budgets 9% of it for groceries. 9% of $2940 is $265 dollars.

Hope this helps!

7 0

2 years ago