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3 years ago

13

A store owner buys backpacks at a certain price and sells them at a higher price. The difference is called the markup. If she pa

ys $21 for a backpack and add a 40% markup on the price, what is the selling price?

2 answers:

Oliga [24]3 years ago

7 0

Answer:8.40

Step-by-step explanation:

21 * .40= 8.40

Sidana [21]3 years ago

6 0

Answer:

I think it is 61 dollar. I wish this helps. ;)

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What is the area of a rectangle measuring 25 feet long by 8 feet wide

Anton [14]

You need to multiply 25 by 8 so the answer well be 200

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lawyer [7]

Answer:

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Step-by-step explanation:

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2 years ago

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Solve the system of equations using the substitution method. 2x+8y=4 x=−3y+5

goldenfox [79]

Since x=-3y+5, substitute x for -3y+5.

2(-3y+5)+8y=4

Distribute.

-6y+10+8y= 4

2y+10= 4

Subtract 10 on both sides.

2y=-6

Divide by 2.

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Plug in y=-3.

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(14,-3)

We can check this.

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3 years ago

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Answer:

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3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

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3 years ago

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