3(-64/8)+25 will give you a positive value of 1
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Answer: (b)-175 ft
Step-by-step explanation:
In 
![\angle ACB=\angle ECD\quad [\text{vertically opposite angles}]\\\angle ABC=\angle CDE\quad [\text{Each angle is }90^{\circ}]\\\therefore \triangle ABC \sim\ \triangle CDE\quad [\text{by AA similarity criteria}]](https://tex.z-dn.net/?f=%5Cangle%20ACB%3D%5Cangle%20ECD%5Cquad%20%5B%5Ctext%7Bvertically%20opposite%20angles%7D%5D%5C%5C%5Cangle%20ABC%3D%5Cangle%20CDE%5Cquad%20%5B%5Ctext%7BEach%20angle%20is%20%7D90%5E%7B%5Ccirc%7D%5D%5C%5C%5Ctherefore%20%5Ctriangle%20ABC%20%5Csim%5C%20%5Ctriangle%20CDE%5Cquad%20%5B%5Ctext%7Bby%20AA%20similarity%20criteria%7D%5D)
(ii)for similar triangles, we can write

Answer:
Step-by-step explanation:
(B) The is answer is q^18
q*q*q*q*q*q*q*q*q = q^9
Then
q^9^2 = 9*2 = q^18