Question

Which of the following represents 3x-5y+10=0 written in slope-intercept form?

Answer 1

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:

$3x-5y + 10 = 0$

We manipulate algebraically:

We subtract 10 from both sides of the equation:

$3x-5y = -10$

We subtract 3x from both sides of the equation:

$-5y = -3x-10$

We multiply by -1 on both sides of the equation:

$5y = 3x + 10$

We divide between 5 on both sides of the equation:

$y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2$

Thus, the equation in the slope-intercept form is $y = \frac {3} {5} x + 2$

Answer:

$y = \frac {3} {5} x + 2$