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3 years ago

Which of the following represents 3x-5y+10=0 written in slope-intercept form?

Mathematics

1 answer:

taurus [48]3 years ago

5 0

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:

$3x-5y + 10 = 0$

We manipulate algebraically:

We subtract 10 from both sides of the equation:

$3x-5y = -10$

We subtract 3x from both sides of the equation:

$-5y = -3x-10$

We multiply by -1 on both sides of the equation:

$5y = 3x + 10$

We divide between 5 on both sides of the equation:

$y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2$

Thus, the equation in the slope-intercept form is $y = \frac {3} {5} x + 2$

Answer:

$y = \frac {3} {5} x + 2$

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The answer would be 92 for this problem

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3 years ago

Simplify by using the law of indices: y^a(b+c)×y^b(c-a)×y^c(a-b)

tia_tia [17]

Answer:

$y^{2ac}$

Step-by-step explanation:

Using the law if indices

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

Thus to simplify the expression add the 3 exponents

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= 2ac

Then the expression simplifies to

$y^{2ac}$

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2 years ago

You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In

alexandr1967 [171]

C. $360

$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)

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3 years ago

Read 2 more answers

What is y+4=-6(x+6) in standred form

max2010maxim [7]

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3 years ago

The ubiquitous 12oz aluminum cans used to distribute drinks in this country have a diameter of approximately 2.75 inches and a h

gayaneshka [121]

Answer:

3.5%

Step-by-step explanation:

The volume of a cylinder = $\pi r^2h$

r = radius of cylinder,

h = height of cylinder

For the non-optimal can,

r = 2.75/2 = 1.375

h = 5.0

$V = \pi(1.375^2)\times 5.0 = 9.453125\pi$

For the optimal can,

d/h = 1,

d = h

2r = h

r = h/2

$V = \pi\left(\dfrac{h}{2}\right)^2\times h = \pi\left(\dfrac{h^3}{4}\right)$

They have the same volume.

$\pi\dfrac{h^3}{4} = 9.453125\pi$

$h^3 = 37.8125$

$h=3.36$ (This is the height of the optimal can)

$r = \dfrac{3.36}{2} = 1.68$ (This is the radius of the optimal can)

The area of a cylinder is

$A = 2\pi r(r+h)$

For the non-optimal can,

$A = 2\pi\times\dfrac{2.75}{2}\left(\dfrac{2.75}{2}+5.0\right) = 17.53125\pi$

For the optimal can,

$A = 2\pi\times1.68\left(1.68+3.36\right) = 16.9344\pi$

Amount of aluminum saved, as a percentage of the amount used to make the optimal cans = $\dfrac{17.53125\pi - 16.9344\pi}{16.9344\pi}\times 100\% = 3.5\%$

5 0

3 years ago