Answer:
We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 29
Sample mean, = 30
Sample size, n = 47
Alpha, α = 0.05
Population standard deviation, σ = 5
First, we design the null and the alternate hypothesis
a) This is a one-tailed test because the alternate hypothesis is in greater than direction.
We use One-tailed z test to perform this hypothesis.
b)
, we reject the null hypothesis and accept the alternate hypothesis and if
, we accept the null hypothesis and reject the alternate hypothesis.
c) Formula:
Putting all the values, we have
d) Now,
Since,
We accept the null hypothesis and reject the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.
e) P-value is 0.0853
On the basis of p value we again accept the null hypothesis.
Answer:
cindy=15 grandmother=75
Step-by-step explanation:
90 divide 6 equal to 15
16
x * 3 = 48
so divide 48 by 3
which is 16 so x = 16
Answer:
ok so you should get -5/24 in simplest form.
Decimal form- -0.2083 repeating
Step-by-step explanation:
Hope this helped :)
Answer: 0.3439
Step-by-step explanation:
Given :The last four digits for telephone numbers are randomly selected (with replacement).
Here , each position can be occupied with any of the digit independently .
Total digits = 10
Total digits other than 0 = 9
For each digits , the probability that it is not 0 =
If we select 4 digits , The probability of getting no 0 =
(By multiplication rule of independent events)
Now , the probability that for one such phone number, the last four digits include at least one 0. = 1- P(none of them is 0)
=1- 0.6561=0.3439
Hence, the probability that for one such phone number, the last four digits include at least one 0. is 0.3439 .