The sum of three consecutive even numbers is 36. what is the smallest of these numbers?
1 answer:
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Call the first even number '2n'
Thus, the next would be 2n + 2
And the next would be 2n + 4
Form an equation:
2n + 2n + 2 + 2n + 4 = 36
Simplify:
6n + 6 = 36
Subtract 6 from both sides:
6n = 30
Divide both sides by 6:
n = 5
2(5) = 10
The smallest number is 10
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