Answer:
The one falling from the greatest height will have the greatest speed.
h = 1/2 g t^2 time for ball to fall distance h
h2 / h1 = t2^2 / t1^2 dividing equations
h2 / t2^2 = h1 / t1^2
Let v be the average speed (v2 = h2 / t2)
1 / t2 * v2 = 1 / t1 * v1
v2 / v1 = t2 / t1 the one taking the longest to fall has the greater av. speed
Check:
h4 / h1 = t4^2 / t1^2 or
t4 / t1 = (h4 / h1)^1/2
In this case t4 / t1 = (4 / 1)^1/2 = 2 or twice the average speed
t1 = (2 h / g)^1/2 = .2^1/2 = .447 using g = 10
t4 = (2 h / g)^1/2 = .8^1/2 = .894
v1 = 1 / .447 = 2.24 m/s average speed
v4 = 4 / .894 = 4.47 or twice the average speed
Since the man and the walkway has velocity (which is a vector) moving in the same direction, who would add the velocities together.
That means the relative velocity would be 2 m/s to the East
If you picture it in your mind, imagine walking down an escalator, you feel like you're moving faster than you really are.
In a different example, if the man was moving 0.9 m/s to the West, they are moving in opposite directions, which means you would subtract the 2 velocities.
Answer:
a = 129.663 ![rad/s^{2}](https://tex.z-dn.net/?f=rad%2Fs%5E%7B2%7D)
Explanation:
We know that:
T = Ia
Where T is the torque, I is the moment of inertia and a is the angular aceleration:
First, we will find the moment of inertia using the following equation:
I = ![\frac{1}{2}MR^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DMR%5E2)
Where M is the mass and R is the radius of the disk. Replacing values, we get:
I = ![\frac{1}{2}(1.29kg)(1.184m)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%281.29kg%29%281.184m%29%5E2)
I = 0.904 kg*m^2
Second, we will find the torque using the following equation:
T = (
)*(R)
Where
is the force on one side and
is the force on the other side. Replacing values, we get:
T = (162N-63N)(1.184m)
T = 117.216N*m
Finally, we replace T and I on the initial equation as:
T = Ia
117.216N = (0.904)(a)
Solving for a:
a = 129.663 ![rad/s^{2}](https://tex.z-dn.net/?f=rad%2Fs%5E%7B2%7D)
All isotopes contain different number of neutrons then the original element
Answer:
To derive the fourth equation of motion, first we have to consider the equation for acceleration and then to rearrange it. or v2 = u2 + 2as and this equation of motion can be used to find the final velocity or the distance travelled if the other values are given.
Explanation:
v= u + at
s =( u + v ) t /2
s = ut + at2/2
v2 = u2 + 2as