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statuscvo [17]
3 years ago
13

The engine of a 2000 kg Mercedes going up Pike’s Peak delivers energy to its drive wheel at the rate 100 kW . Neglecting air res

istance, what is the largest speed the car can sustain on the steep Pike’s Peak mountain highway, where the road is 30◦ to the horizontal? The acceleration due to gravity is 10 m/s 2 .
Physics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

v = 10 m/s

Explanation:

given,

Mass of Mercedes engine = 2000 Kg

Power delivered = 100 kW

angle made with horizontal = 30°

acceleration due to gravity =  10 m/s²

largest speed car can sustain = ?

we know,

Power = Force x velocity

P = F x v

P = mg sinθ x v

P = mg sin 30° x v

P = 0.5 mg  x v

v = \dfrac{100 \times 10^3}{0.5\times 2000 \times 10}

v = 10 m/s

hence, the maximum velocity is equal to v = 10 m/s

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Number 12 gauge wire, commonly used in household wiring, is 2.053mm in diameter and can safely carry up to 20A. For a wire carry
Likurg_2 [28]

Answer:

The magnetic field strength is 3.9 x 10⁻³ T

Explanation:

The equation for the magnetic field strength produced by a long straight current-carrying wire is written as;

B = \frac{\mu_o I }{2\pi r}

Where;

μ₀ is constant = 4π x 10⁻⁷ N/A

I is the maximum current = 20 A

r is the radius of the wire = 2.053/2 = 1.0265 mm = 1.0265 x 10⁻³ m

Substitute in this values into the equation above;

B = \frac{4 \pi X10^{-7} X 20}{2\pi X 1.0265X10^{-3} } \\\\B =3.9 X10^{-3} T

Therefore, the magnetic field strength is 3.9 x 10⁻³ T

8 0
3 years ago
As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in
Semenov [28]

Answer:

A_2 = 2.5\ cm^2

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}

\dfrac{10}{A_2} =4

\dfrac{10}{4} =A_2

A_2 = 2.5\ cm^2

hence, the area of capillaries is equal to 2.5 cm₂

4 0
2 years ago
Find the density of seawater at a depth where the pressure is 680 atm if the density at the surface is 1030 kg/m3. Seawater has
Pie

Answer:

1060.41kg/m^3

Explanation:

Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:

B=\rho _o \frac{\bigtriangleup P }{\bigtriangleup \rho}

Hence the density of the seawater at a depth of 680atm is calculated as:-

\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+\frac{\bigtriangleup P}{B})\\\\=1030 \times (1+ \frac{(680-1)\times10^5}{2.3\times 10^9})\\=1060.41kg/m^3

4 0
3 years ago
What is a discussion?
kap26 [50]

Answer:

um, when you talk with other people about stuff. (I'm not trying to sound like a smarta s s I'm just giving a definition...)

Explanation:

7 0
3 years ago
Read 2 more answers
If a boat and its riders have a mass of 900 kg and the boat drifts in at 1.4 m/s how much work does sam do to stop it?
Rama09 [41]
The initial kinetic energy of the boat and its rider is
K_i =  \frac{1}{2} mv_i^2 =  \frac{1}{2}(900 kg)(1.4 m/s)^2=882 J

After Sam stops it, the final kinetic energy of the boat+rider is
K_f = 0 J
because its final velocity is zero.

For the law of conservation of energy, the work done by Sam is the variation of kinetic energy of the system:
W=K_f-K_i =0-882 J=-882 J
where the negative sign is due to the fact that the force Sam is applying goes against the direction of motion of the boat.
6 0
3 years ago
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