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yKpoI14uk [10]
3 years ago
11

1. (a) The battery on your car has a rating stated in ampere-minutes which permits you to

Physics
1 answer:
Alborosie3 years ago
6 0

Answer:

Energy is stored by a 50 ampere-minute 12

volt battery is approximately = 36,000 J = 36 kJ

Explanation:

Power in electrical circuits is given as

Power = IV

But power generally is defined as energy expended per unit time

Power = (Energy/time)

Energy = Power × Time

Energy = IV × Time

Energy = (I.t × V)

I.t = 50 Ampere-minute = 50 × 60 = 3000 Ampere-seconds

V = 12 V

Energy = 3,000 × 12 = 36,000 J = 36 kJ

Hope this Helps!!!

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A secret agent is locked in a room. He pushes against the door but cannot open it. Finally, he falls to the floor exhausted. Has
Vitek1552 [10]

Answer: There is not work done at the door because the door did not move.

Explanation:  Work is defined as the movement done by a force.

So if you move to apply a force F in an object and you move it a distance D, the work applied on the object is  

W = F*D

In this case, the secret agent pushes against the door, so there is a force, but the agent does not move the door, so D = 0, so there is no motion of the door, which implies that there is no work done at the door.

8 0
3 years ago
What is a hypothisis​
Ostrovityanka [42]

Answer:

a precise, testable statement of what the reseatcher predict will be the outcome of the study

Explanation:

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While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the
Grace [21]

Complete Question

While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the system's center of mass. From their color and brightness, you determine that each star has the same mass as our Sun. The orbital period of the pair is 29.3 days , based on the oscillation of brightness observed as one star occludes (hides) the other. From this information you are able to ascertain the distance between the stars.

Calculate the distance between the stars.

Express your answer to two significant digits and include the appropriate units.

Answer:

The distance between the stars is d =3.50*10^{30}m

Explanation:

 From this question we are told that

         The orbital period is 29.3 \ days = 29.3 *24 *60* 60 = 210960\ sec

         The mass of the stars are = Mass of sun = 1.99*10^{30}kg

         

For the two stars to keep on rotating on the circular orbit, the gravitational force must equal to the centripetal force and this can be mathematically represented as

                \frac{Gm^2}{d^2} = \frac{mv^2}{r}

Where r is the radius of the circular orbit

            G is the gravitational constant =6.67 *10 ^{-11}

           d  is the linear distance between the two stars = 2 r

This because during their oscillation around the circular orbit one usually hides the other

           v = \frac{2 \pi r }{T}

   Now substituting values into the above relation

              \frac{Gm^2}{(2r)^2} = \frac{m[\frac{2 \pi r}{T} ]^2}{r}

              \frac{Gm^2}{(2r)^2} = \frac{m[\frac{4 \pi^2 r^2  }{T} ]}{r}

                 r^3 = [\frac{GmT^2}{16 \pi^2} ]

Substituting values we have

                r = [\frac{(6.67*10^{-11})(1.99*10^{30})(2531520)^2}{16(3.142)^2} ]^{\frac{1}{3} }

                   =\sqrt[3]{5.38529*10^{30}}

                   =1.75*10^{30}m

Now d = 2r

=> d  =2 *1.75*10^{30}m

        =3.50 *10^30m

6 0
4 years ago
4. How far apart are a proton and electron if they exert an attractive force of 3 N on one another?
alexandr402 [8]

Answer:

8.76\cdot 10^{-15}m

Explanation:

The magnitude of the electrostatic force between two charges is given by the equation:

F=k\frac{q_1 q_2}{r^2}

where:

k=9\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

And the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

F = 3 N is the force between the proton and the electron

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the charge of the proton and the electron

Therefore, solving for r, we find the separation between the two particles:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(9\cdot 10^9)(1.6\cdot 10^{-19})^2}{3}}=8.76\cdot 10^{-15}m

5 0
3 years ago
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