Answer: There is not work done at the door because the door did not move.
Explanation: Work is defined as the movement done by a force.
So if you move to apply a force F in an object and you move it a distance D, the work applied on the object is
W = F*D
In this case, the secret agent pushes against the door, so there is a force, but the agent does not move the door, so D = 0, so there is no motion of the door, which implies that there is no work done at the door.
Answer:
a precise, testable statement of what the reseatcher predict will be the outcome of the study
Explanation:
the above three pictures may help you
go through the attachments
Complete Question
While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the system's center of mass. From their color and brightness, you determine that each star has the same mass as our Sun. The orbital period of the pair is 29.3 days , based on the oscillation of brightness observed as one star occludes (hides) the other. From this information you are able to ascertain the distance between the stars.
Calculate the distance between the stars.
Express your answer to two significant digits and include the appropriate units.
Answer:
The distance between the stars is 
Explanation:
From this question we are told that
The orbital period is 
The mass of the stars are = Mass of sun 
For the two stars to keep on rotating on the circular orbit, the gravitational force must equal to the centripetal force and this can be mathematically represented as

Where r is the radius of the circular orbit
G is the gravitational constant 
d is the linear distance between the two stars = 2 r
This because during their oscillation around the circular orbit one usually hides the other

Now substituting values into the above relation
![\frac{Gm^2}{(2r)^2} = \frac{m[\frac{2 \pi r}{T} ]^2}{r}](https://tex.z-dn.net/?f=%5Cfrac%7BGm%5E2%7D%7B%282r%29%5E2%7D%20%3D%20%5Cfrac%7Bm%5B%5Cfrac%7B2%20%5Cpi%20r%7D%7BT%7D%20%5D%5E2%7D%7Br%7D)
![\frac{Gm^2}{(2r)^2} = \frac{m[\frac{4 \pi^2 r^2 }{T} ]}{r}](https://tex.z-dn.net/?f=%5Cfrac%7BGm%5E2%7D%7B%282r%29%5E2%7D%20%3D%20%5Cfrac%7Bm%5B%5Cfrac%7B4%20%5Cpi%5E2%20r%5E2%20%20%7D%7BT%7D%20%5D%7D%7Br%7D)
![r^3 = [\frac{GmT^2}{16 \pi^2} ]](https://tex.z-dn.net/?f=r%5E3%20%3D%20%5B%5Cfrac%7BGmT%5E2%7D%7B16%20%5Cpi%5E2%7D%20%5D)
Substituting values we have
![r = [\frac{(6.67*10^{-11})(1.99*10^{30})(2531520)^2}{16(3.142)^2} ]^{\frac{1}{3} }](https://tex.z-dn.net/?f=r%20%3D%20%5B%5Cfrac%7B%286.67%2A10%5E%7B-11%7D%29%281.99%2A10%5E%7B30%7D%29%282531520%29%5E2%7D%7B16%283.142%29%5E2%7D%20%5D%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D)
![=\sqrt[3]{5.38529*10^{30}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B5.38529%2A10%5E%7B30%7D%7D)

Now d = 2r
=> d 

Answer:

Explanation:
The magnitude of the electrostatic force between two charges is given by the equation:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
And the force is:
- Attractive if the charges have opposite sign
- Repulsive if the charges have same sign
In this problem, we have:
F = 3 N is the force between the proton and the electron
is the magnitude of the charge of the proton and the electron
Therefore, solving for r, we find the separation between the two particles:
