8.0 m/s if there is no air resistance. (B)
Less if there IS any air resistance.
Answer:
70.5 mph
Explanation:
A passenger jet travels from Los Angeles to Bombay, India, in 22h.
The return flight takes 17 h.
The difference in flight times is caused by winds over the Pacific Ocean that
blow primarily from west to east.
If the jet's average speed in still air is 550 mi/h what is the average speed
of the wind during the round trip flight? Round to the nearest mile per hour.
Is your answer reasonable?
:
Let w = speed of the wind
:
Write a distance equation (dist is the same both ways
17(550+w) = 22(550-w)
9350 + 17w = 12100 - 22w
17w + 22w = 12100 - 9350
39w = 2750
W = 2750/39
w = 70.5 mph seems very reasonable
:
Confirming if the solution by finding the distances using these value
17(550+70.5) = 10549 mi
22(550-70.5) = 10549 mi; confirms our solution of w = 70.5 mph
Answer:
The ratio of the Broglie wavelength of an electron to that of the proton is 42.85.
Explanation:
let λe be the Broglie wavelength of the electron and λp be the Broglie wavelength of the proton, Me be the mass of the electron and Mp be the mass of the proton. let h be the Planck constant, Kep be the kinetic energy of the proton and KEe be the kinetic energy of the electron
The correct option is C i..e.
change the second medium to get a greater difference than before in the speed of light in the two mediums
Explanation: whenever light goes from one medium to another, kts frequency remains unchanged. It totally depends on tbe refractive index of the medium, which can change the speed of light.
If the refractive index of the entering medium is less than that of the medium from which light came,then the angle will be wider.