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Luba_88 [7]
3 years ago
10

How many electrons are depicted in the electron dot diagram of an electrically neutral nitrogen atom? A. two B. six C. eight D.

five
Physics
2 answers:
ella [17]3 years ago
8 0
The amount of electron that are depicted in the electron dot diagram of an electrically neutral nitrogen atom is : D. Five
In ELectron dot diagram, the one that being showed is only the outer energy level

Hope this helps
goldenfox [79]3 years ago
4 0

Answer is D - five.


<em>Explanation;</em>


- Electron dot diagrams show the valence electrons around the element by using dots.


- Valence electrons are the electrons which are in outermost shell of the atom.


-The atomic number of the N atom is 7.

      Atomic number = number of protons = 7

  If the atom is neutral,

      number of protons = number of electrons.


  Hence, N atom has 7 electrons.


- The electron configuration is 1s² 2s² 2p³.


Hence, N atom has 2 + 3 = 5 valence electrons. So, five electrons are represented in electron dot diagram of N.

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Complete question is;

Jason works for a moving company. A 75 kg wooden crate is sitting on the wooden ramp of his truck; the ramp is angled at 11°.

What is the magnitude of the force, directed parallel to the ramp, that he needs to exert on the crate to get it to start moving UP the ramp?

Answer:

F = 501.5 N

Explanation:

We are given;

Mass of wooden crate; m = 75 kg

Angle of ramp; θ = 11°

Now, for the wooden crate to slide upwards, it means that the force of friction would be acting in an opposite to the slide along the inclined plane. Thus, the force will be given by;

F = mgsin θ + μmg cos θ

From online values, coefficient of friction between wooden surfaces is μ = 0.5

Thus;

F = (75 × 9.81 × sin 11) + (0.5 × 75 × 9.81 × cos 11)

F = 501.5 N

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3 years ago
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Explanation:

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Answer:

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Explanation:

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T = -131 + ( 0.003 * altitude in meters )

  =  -131 + ( 0.003 * 19500 ) = - 72.5°c

b) Determine pressure and density at 19.5 km altitude

Given :

Po (atmospheric pressure at sea level )  = 101kpa

R ( gas constant of air ) = 0.287 KJ/Kgk

T = -72.5°c ≈ 200.5 k

pressure = 3625.13 Pa

hence density = 0.063 kg/m^3

attached below is the remaining part of the solution

C) determine if the aircraft is subsonic or super sonic

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4 0
3 years ago
A drop of oil of volume 10m it spread out on water to make a circular firm of radius 10m calculate the tickness of the firm
Effectus [21]

Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

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So, the thickness of the film is equal to 3.1 cm.

8 0
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