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WINSTONCH [101]
3 years ago
10

What is the surface area-to-volume ratio of a 5 cm cube?

Mathematics
1 answer:
Fed [463]3 years ago
4 0
Surface area=5*5*6=150

volume=5*5*5=125

surface area:volume=150:125=6:5

The answer is 6:5
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1. Find<br> the area of each figure to the nearest tenth.
ELEN [110]

Area = 85ft²

To find the area of the given square you can use the following equation

Area = Side^2\\Area = 8^2\\Area = 64

To find the missing side of the given triangle, you will have to use Pythagorean's theorem

Short^2 + Long^2 = Hypotenuse^2\\Short^2 + 8^2 = 10^2\\Short^2 + 64 = 100\\Short^2 = 100 -  64\\Short^2 = 36\\Short= \sqrt{36} \\Short= 6 \\

Now that we know what both sides are we can use the following equation to get the area of the triangle

Area = \frac{Side*Side}{2} \\Area = \frac{6*8}{2} \\Area = \frac{42}{2} \\Area = 21 \\

After that, we can add both areas together and get the following

21+64=85

8 0
3 years ago
Read 2 more answers
..vertex: (4, -1)<br> f(3) = -6
s344n2d4d5 [400]

Answer:

\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}

Step-by-step explanation:

The vertex form of an equation of a parabola:

f(x)=a(x-h)^2+k

(h;\ k) - vertex

We have

vertex (4;\ -1)\to h=4;\ k=-1

f(3)=-6

Therefore we have:

f(x)=a(x-4)^2+(-1)=a(x-4)^2-1

Substitute x=3 and f(3)=-6

a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5

Finally:

f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81

4 0
3 years ago
Expand and simplify 5(2x-1) + 2(3x-6)
aleksklad [387]
5                     (2x-1)     +            2(3x-6)

I could only expand it :)
8 0
3 years ago
Find the midpoint of segment JT when the coordinates are J(-3,18) and T(7,-10). Show all work
nignag [31]
Given two points (x₁,y₁) and (x₂,y₂), the midpoint of the segment will be:
( (x₁+x₂) / 2 , (y₁+y₂)/2  ).
In this case:
J(-3,18)
T(7,-10)

The midpoint will be:
( (-3+7)/2  ,  (18-10)/2 )=(4/2 , 8/2)=(2, 4).

Answer: the midpoint of segment JT is (2,4)
5 0
3 years ago
What is the volume of a hemisphere with a radius of 9.8 in, rounded to the nearest tenth of a cubic inch?​
pogonyaev

Answer:

the volume of the hemisphere is 1970.2 cubic inches.

Step-by-step explanation:

The given is,

                  Radius of hemisphere is 9.8 inches.

Step:1

                 Formula of volume of hemisphere is,

                             ..................(1)

                 Where,

                           r - Radius of hemisphere

Step:2

                 From the given,

                          r = 9.8 inches

                 Equation (1) becomes,

                             

                                                 =  

                                                 =                    

                                                 = (0.66666666)(3.1415)(942.192)  

                                                 = 1971.23

          Volume of hemisphere = 1971.23 cubic inches

Result:is 1970.2 cubic inches.

7 0
3 years ago
Read 2 more answers
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