2nd one is the correct one I think
Answer:
Step-by-step explanation:
A scalar is a constant value that is multiplied throughout a matrix.
e.g.
In number 1 the set up would look like this
3 * ![\left[\begin{array}{ccc}3&-1&5\\2&1&-4\\-6&3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-1%265%5C%5C2%261%26-4%5C%5C-6%263%262%5Cend%7Barray%7D%5Cright%5D)
To solve this, you must distribute the 3 to each value within the matrix
The solution to #1 would be
M = ![\left[\begin{array}{ccc}9&-3&15\\6&3&-12\\-18&9&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-3%2615%5C%5C6%263%26-12%5C%5C-18%269%266%5Cend%7Barray%7D%5Cright%5D)
1000 j etyuu was the night of my school week I am so
Well, I would just reverse it. It seems you just have to reverse the whole problem.
Lap 2 because the bigger the number in time the longer.