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marta [7]
3 years ago
6

A game is played where players take turns rolling two six-sided dice, each with sides numbered 1-6. The numbers on the two dice

are added together for each player's score. If the first player rolls a sum of 10, what is the probability that the second player rolls a HIGHER total?
Mathematics
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

\frac{1}{12}

Step-by-step explanation:

Total number of possible outcomes when a dice is rolled six times

= 6*6\\= 36

Number of possible outcomes than have a sum greater than 10 are

(6,5)\\(5,6)\\(6,6)\\

Probability that the second player rolls a total higher than 10 is equal to the total number of possible outcomes with sum greater than 10 divided by total outcomes

\frac{3}{36} \\= \frac{1}{12}

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