The value of which number lies between 14 and 15?

You are considering changing insurance companies. Your current company charges you $1500 per year for homeowners insurance plus

Gwar [14]

First, write an equation for each scenario.

$300 quarterly is equivalent to $1200 a year.

The first equation is y= 2700x.

The second equation is y=2700x.

The answer is both; their deals are the same.

7 0

3 years ago

During a period of 11 years 737737 of the people selected for grand jury duty were sampled, and 6868% of them were immigrants.

Galina-37 [17]

The formula to set out the lower and the upper margin of a confidence interval when given the proportion (no standard deviation) is

Lower margin = p - Z* √[(pq) ÷ n]
Upper margin = p + Z* √[(pq) ÷ n]

Where:
p is the sample proportion
q is 1 - p
Z* is the z-score for the confidence level
n is the number size
--------------------------------------------------------------------------------------------------------------

p = (68% of 737) ÷ 737 = 501.16 ÷ 737 = 0.68
q = 1 - p = 1 - 0.68 = 0.32
Z* = 2.58 (refer to the table attached below)
n = 737

substituting these values into the formula, we have

lower margin = 0.68 - (2.58) √[(0.68×0.32) ÷ 737]
lower margin = 0.68 - (2.58) √(0.0002952510176...)
lower margin = 0.68 - 0.04433180431
lower margin = 0.6357 (rounded to four decimal places)
lower margin = 63.57%

upper margin = 0.68 + 0.04433180431
upper margin = 0.7243 (rounded to four decimal places)
upper margin = 72.43%

The confidence interval is between 63.57% and 72.43%. In other words, we can say that between 63.57% and 72.43% of jury members are immigrant.

The claim of 69.46% is within the confidence interval, hence we can conclude that the selection of grand jury duty is not biased against the immigrant.

8 0

3 years ago

Guys plz help me!!!!!!!!

Rainbow [258]

Answer:

63.62

Step-by-step explanation:

3 0

2 years ago

Rewrite the following integral in spherical coordinates.

lora16 [44]

In cylindrical coordinates, we have $r^2=x^2+y^2$ , so that

$z = \pm \sqrt{2-r^2} = \pm \sqrt{2-x^2-y^2}$

correspond to the upper and lower halves of a sphere with radius $\sqrt2$ . In spherical coordinates, this sphere is $\rho=\sqrt2$ .

$1 \le r \le \sqrt2$ means our region is between two cylinders with radius 1 and $\sqrt2$ . In spherical coordinates, the inner cylinder has equation

$x^2+y^2 = 1 \implies \rho^2\cos^2(\theta) \sin^2(\phi) + \rho^2\sin^2(\theta) \sin^2(\phi) = \rho^2 \sin^2(\phi) = 1 \\\\ \implies \rho^2 = \csc^2(\phi) \\\\ \implies \rho = \csc(\phi)$

This cylinder meets the sphere when

$x^2 + y^2 + z^2 = 1 + z^2 = 2 \implies z^2 = 1 \\\\ \implies \rho^2 \cos^2(\phi) = 1 \\\\ \implies \rho^2 = \sec^2(\phi) \\\\ \implies \rho = \sec(\phi)$

which occurs at

$\csc(\phi) = \sec(\phi) \implies \tan(\phi) = 1 \implies \phi = \dfrac\pi4+n\pi$

where $n\in\Bbb Z$ . Then $\frac\pi4\le\phi\le\frac{3\pi}4$ .

The volume element transforms to

$dx\,dy\,dz = r\,dr\,d\theta\,dz = \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi$

Putting everything together, we have

$\displaystyle \int_0^{2\pi} \int_1^{\sqrt2} \int_{-\sqrt{2-r^2}}^{\sqrt{2-r^2}} r \, dz \, dr \, d\theta = \boxed{\int_0^{2\pi} \int_{\pi/4}^{3\pi/4} \int_{\csc(\phi)}^{\sqrt2} \rho^2 \sin(\phi) \, d\rho \, d\phi \, d\theta} = \frac{4\pi}3$

4 0

2 years ago

Two adjacent supplementary angles form a

Sedbober [7]

Obtuse because it all adds up to 180 degrees <span />

4 0

3 years ago