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3 years ago

7

Leah mowed 18 lawns in 15 hours. What was her rate of mowing in hours per lawn?Express ur answer in the simpilest form.

2 answers:

wolverine [178]3 years ago

8 0

If she mowed 18 lawns in 15 hours and didn’t get paid she would be dumb but if she did get paid the answer is 1.76

iogann1982 [59]3 years ago

5 0

Answer:

5/6 hours per lawn

Step-by-step explanation:

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Savannah is writing an article for the school paper on the next school election. She surveys 20 of her friends and finds that 17

Sonbull [250]

Answer:

A. The students were not chosen randomly.

Step-by-step explanation:

4 0

3 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

3 years ago

A treasure chest sinks at a rate no less than 20 ft per second. The floor of the ocean is at most at -4200 feet. Will the treasu

SashulF [63]

4200ft divided by 20 ft per second divided by 60 seconds is 1400 minutes

5 0

3 years ago

Can you please help me?

d1i1m1o1n [39]

Answer:

C / (2 pi) = r

Step-by-step explanation:

C = 2 pi r

Divide each side by 2 pi

C / (2 pi) = 2 pi r/ (2 pi)

C / (2 pi) = r

3 0

2 years ago

"let v = r 2 with the usual addition and scalar multiplication defined by k(u1, u2) = (ku1, 0). determine which of the five axio

expeople1 [14]

Let $\mathbf u\in\mathbb R^2$ , where

$\mathbf u=(u_1,u_2)$

and let $k\in\mathbb R$ be any real constant.

Given this definition of scalar multiplication, we can see right away that there is no identity element $e$ such that

$e\mathbf u=\mathbf u$

because

$e\mathbf u=e(u_1,u_2)=(eu_1,0)\neq(u_1,u_2)=\mathbf u$

5 0

3 years ago