Many physical quantities are connected by inverse square laws, that is, by power functions of the form f(x)=kx^(-2). In particul
1 answer:
Answer:
- 4 times
Explanation:
Since the equation for the illumination of an object, i.e. the brightness of the light, is <em>inversely proportional to the square of the distance from the light source</em>, the form of the function is:
- f(x) = k.x⁻²
Where x is the distance between the object and the light force, k is the constant of proportionality, and f(x) is the brightness.
Then, if you move halfway to the lamp the new distance is x/2 and the new brightness (call if F) is :
Then, you have found that the light is 4 times as bright as it originally was.
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To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to
Here
= True Weight
= Apparent Weight
= Buoyant Force
If we seek to find the apparent weight we will have to,
Remember that
V = Volume (Volume Sphere)
= Density (At this case water density)
g = Gravitational acceleration
Therefore the apparent weight will be 0.1526N
Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity
and the distance covered along the horizontal direction in a time t is
- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity and constant acceleration
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is
The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:
Substituting and solving for t, we find:
b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:
The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem: