Answer:
Explanation:
Given
mass of hot metal 
specific heat 
mass of water 
Temperature pf water 
Final Temperature 
let
be the temperature of hot metal ball
Heat lost by heat metal bolt is gained by water in calorimeter
Heat lost by hot metal bolt 

Heat gained by water 





Answer:
Solon,
total mass (kg)= 100kg
height (h)= 25m
acceleration due to gravity = 9.8m/s²
so,
work done =m*g*h
= 100*9.8*25
= 24,500 joule
Answer:
An ion.
Explanation:
Atoms can gain or lose electrons and become ions, which are atoms that have a positive or negative charge, because they have unequal numbers of protons and electrons.
Answer:
See explanation
Explanation:
The degradation of the drug is a first order process;
Hence;
ln[A] = ln[A]o - kt
Where;
ln[A] = final concentration of the drug
ln[A]o= initial concentration of the drug = 5 gm/100
k= degradation constant = 0.05 day-1
t= time taken
When [A] =[ A]o - 0.5[A]o = 0.5[A]o
ln2.5 = ln5 - 0.05t
ln2.5- ln5 = - 0.05t
t= ln2.5- ln5/-0.05
t= 0.9162 - 1.6094/-0.05
t= 14 days
b) when [A] = [A]o - 0.9[A]o = 0.1[A]o
ln0.5 = ln5 -0.05t
t= ln0.5 - ln5/0.05
t= -0.693 - 1.6094/-0.05
t= 46 days