Answer:
153.6 kN
Explanation:
The elastic constant k of the block is
k = E * A/l
k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m
0.12% of the original length is:
0.0012 * 0.25 m = 0.0003 m
Hooke's law:
F = x * k
Where x is the change in length
F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)
The compressive load will generate a stress of
σ = F / A
F = σ * A
F = 80*10^6 * 0.048 * 0.04 = 153.6 kN
The smallest admisible load is 153.6 kN
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
Answer:
Rf5 is 6 and I have an article on common strategies for coping
Explanation:
Abdullah and this is my 55 566 and I have an article on common strategies for coping with the value of polynomial 5x and the video will will certainly not cause any harm to you and the thank god that you can please make a gaming video or 6 with gggtgr and the video will will certainly be the same as the one you sent me last night and I will send you a link to the chief 6 on the
Answer:
a. Fr^2 = 119.7^2 + 49.9^2 = 16,818.1
Fr = 129.7 N.
b. tanA = Y/X = 49.9/119.7 = 0.41688
A = 22.63o = Direction.
Explanation:
