Answer: T = 93 N
Explanation:
Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.
ΣF = Σma
Mg - mg = Ma + ma
a = g(M - m) / (M + m)
Now looking only at the larger mass as it falls
Mg - T = Ma
T = Mg - Ma
T = Mg - Mg(M - m) / (M + m)
T = Mg(1 -(M - m) / (M + m))
T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))
T = 93 N
or looking only at the smaller mass
T - mg = ma
T = m(g + a)
T = m(g + g(M - m) / (M + m))
T = mg(1 + (M - m) / (M + m))
T = 6.7(9.8)(1 + (16 - 6.7) / (16 + 6.7))
T = 93 N
The momentum of the mass expelled in the opposite direction ... the rocket-engine exhaust, or the ionized matter expelled from an ion drive.
THAT's why every propulsion engine has outlet nozzles designed with super-high-intensity math, to achieve the highest possible velocity for the mass that gets shot out the back ... so that it will carry the maximum possible momentum.
Elastic means that no energy is converted into heat during the collision so kinetic energy before and after the collision remains constant. In both elastic and inelastic collisions, momentum is always conserved.
Trust me, i'm a k12 student and its motor
I wouldn’t click the link above me. Bunch of bots going around
