Answer:
153.6 kN
Explanation:
The elastic constant k of the block is
k = E * A/l
k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m
0.12% of the original length is:
0.0012 * 0.25 m = 0.0003 m
Hooke's law:
F = x * k
Where x is the change in length
F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)
The compressive load will generate a stress of
σ = F / A
F = σ * A
F = 80*10^6 * 0.048 * 0.04 = 153.6 kN
The smallest admisible load is 153.6 kN
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
Answer:
Rf5 is 6 and I have an article on common strategies for coping
Explanation:
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Answer:
a. Fr^2 = 119.7^2 + 49.9^2 = 16,818.1
Fr = 129.7 N.
b. tanA = Y/X = 49.9/119.7 = 0.41688
A = 22.63o = Direction.
Explanation: