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bekas [8.4K]
3 years ago
7

What is the slope of this equation 1/2x - 1/3

Mathematics
2 answers:
viktelen [127]3 years ago
5 0
It is not linear, so therefore no slope
Natasha2012 [34]3 years ago
5 0
The answer to the question

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Explain how to find coordinates for Q
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Q = (4, - 1)

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DF is the diameter of the circle with center Q.

So, Q is the midpoint of DF.

By mid point formula.

Q =  \bigg( \frac{1 + 7}{2},  \:  \:  \frac{3 - 5}{2} \bigg) \\  \\ Q =  \bigg( \frac{8}{2},  \:  \:  \frac{ - 2}{2} \bigg) \\  \\ Q = (4, \:  \:  - 1)

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What’s the answer to f(a)
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3 years ago
If two angles are supplementary to the same angles, then
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The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
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