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Stells [14]
3 years ago
12

Where do cells get the chemicals needed to synthesize other molecules?

Physics
2 answers:
Maslowich3 years ago
6 0

Answer: from the food they take in

The chemicals needed to produce molecules comes from the food which an organism eat. A food is a rich source of fats, oils, proteins, carbohydrates and vitamins which are required by the cells to produce functional molecules necessary for building the body and maintaining it's proper functioning.

jek_recluse [69]3 years ago
4 0
From the food they take in
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Review 1: A plane is located x = 40 miles (horizontally) away from an airport at an altitude of h miles. Radar at the airport de
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Explanation:

Let h is the height of the plane above ground. x is the horizontal distance between the ground and the airport. Let s(t) is the distance between the plane and the airport. So,

s(t)^2={h^2+x^2}...........(1)

Given, h = 4, x = 40 and s(t) = -20 mph

Differentiate equation (1) wrt t

2s(t)s'(t)=2x(t)x'(t)

x'(t)=\dfrac{s(t)s'(t)}{x(t)}

When x = 40, s(t)=\sqrt{40^2+4^2}=40.19\ m

x'(t)=\dfrac{-240s(t)}{x(t)}

x'(t)=\dfrac{-240\times 40.19}{40}

x'(t)=-241.14\ m/s

So, the speed of the airplane is 241.14  m/s. Hence, this is the required solution.

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3 years ago
Will give brainliest to right answer!
viva [34]
The correct answer is D.
8 0
3 years ago
What is the best explanation for why, on average, children playing inside a
Anestetic [448]

Answer:

In a house there is a lot less space so there is no where for the sound to travel, but if you are outside there is a lot more space so therefore, the sound can travel anywhere.

Explanation:

5 0
2 years ago
Please answer this.
lilavasa [31]

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the answer is c

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6 0
3 years ago
Read 2 more answers
Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m
Phoenix [80]

Answer:

a. t_1=12.5\ s

b. a_2=-13.61\ m.s^{-2}  must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c. t_2=2.5714\ s is the time taken to stop after braking

Explanation:

Given:

  • speed of leading car, u_1=25\ m.s^{-1}
  • speed of lagging car, u_{2}=35\ m.s^{-1}
  • distance between the cars, \Delta s=45\ m
  • deceleration of the leading car after braking, a_1=-2\ m.s^{-2}

a.

Time taken by the car to stop:

v_1=u_1+a_1.t_1

where:

v_1=0 , final velocity after braking

t_1= time taken

0=25-2\times t_1

t_1=12.5\ s

b.

using the eq. of motion for the given condition:

v_2^2=u_2^2+2.a_2.\Delta s

where:

v_2= final velocity of the chasing car after braking = 0

a_2= acceleration of the chasing car after braking

0^2=35^2+2\times a_2\times 45

a_2=-13.61\ m.s^{-2} must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c.

time taken by the chasing car to stop:

v_2=u_2+a_2.t_2

0=35-13.61\times t_2

t_2=2.5714\ s  is the time taken to stop after braking

7 0
3 years ago
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