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2 years ago

A 783kg elevator rises straight up 164 meters. What is the potential energy of the elevator?

Physics

2 answers:

Vilka [71]2 years ago

8 0

Answer:

$potential \: energy = mgh \\ m = 783 \\ g = 10 \\ h = 164 \\ pe = 783 \times 10 \times 164 \\ = 7830 \times 164 \\ = 1284120 \: joule \\ thank \: you$

Fittoniya [83]2 years ago

7 0

Explanation:

$\sf \: Mass \: of \: the \: body: 783\: kg$

$\sf \: Acceleration \: due \: to \: gravity : 10$

$\sf \: Height : 164 \: metres$

$\sf\longmapsto \: 783 \times 10 \times 164$

$\sf\longmapsto 7830 \times 164$

$\sf\longmapsto 1284120\:$

$\sf\longmapsto 1284120 \:Joule\:$

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Answer:

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Explanation:

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In equilibrium, the distance between the spheres will be equal to 2 times the length of the string times sin(50):

$r = 2*L*sin(50) = 2 * 0.1m * sin(50) 0.1532 m$

And k is the coulomb constan equal to 9 *10^9 N*m^2/C^2. q1 y q2 is the charge of each particle, in this case, they are equal.

$F_x = T_x - F_e = 0\\T_x = F_e = k*\frac{q^2}{r^2}$

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That is;

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W = work done (J or N/m)

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