A 3.5 V battery is connected to a wire with a resistance of 2.5 Ohms. Use Ohm's law to calculate the current for this wire
2 answers:
Answer:
1.4A
Explanation:
Ohm's law states the the current flowing through a metallic conductor is directly proportional to the potential difference applied across it provided that the temperature and other necessary physical conditions remain constant.
This law is mathematically rendered as follows;
where V is the potential difference, I is the current and R is the resistance of the conductor.
The current I could be determined by making it the subject of formula provided other parameters are known.
Given;
V = 3.5V
R = 3.5Ohms.
We then substitute these into equation(2) to obtain I.
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Answer:
Explanation:
Given that,
Capacitance 1,
Capacitance 2,
Capacitance 3,
C₁ and C₂ are connected in series. Their equivalent is given by :
Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :
So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, 
:
First we need to find the net charge flowing at a certain point of the wire in one second,
. Using I=0.92 A and re-arranging the previous equation, we find
Now we know that each electron carries a charge of
, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
First we need to find the net charge flowing at a certain point of the wire in one second,
Now we know that each electron carries a charge of