Question

What is the 32nd term of 311, 305, 299

Answer 1

Answer:

503

Step-by-step explanation:

For an arithmetic sequence, the n-th term is found by

$a_n = a_1 + (n - 1)d$

To find $d$ (the common difference) we can simply subtract one of the terms by the last, for example:

$d = 299 - 305 \\d = -6$

The common difference must be the same throughout the entire sequence, so we can do it once more just to be sure:

$d = 305 - 311\\d = -6$

We also have to know that $a_1$ stands for the first term of the sequence, which in this case is 311.

Now that we know this, let's find the 32nd term

$a_{32} = 311 + (32 - 1)-6\\a_{32} = 311 + 192\\a_{32} = 503$

Good luck!

Answer 2

Answer:

$a_{32}$ = 125

Step-by-step explanation:

d = - 6

$a_{n}$ = $a_{1}$ + (n - 1)d

$a_{32}$ = 311 + (32 - 1)( - 6) = 125