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Rainbow [258]
3 years ago
5

ASAP JUST ANSWER THX

Mathematics
2 answers:
Vilka [71]3 years ago
7 0
The answer should be “B”
MAVERICK [17]3 years ago
5 0

Answer:

b

Step-by-step explanation:

b

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Explain the polar form in mathematical terms ....... right answer will be mark as brainliest​
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The polar form of a complex number is another way to represent a complex number. The form is called the rectangular coordinate form of a complex number. The horizontal axis is the real axis and the vertical axis is the imaginary axis.
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The function F(x) = 2x/x+3 is an example of a rational function.<br><br><br> True<br> False
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It is true because a rational function is defined as those functions where the variable is placed in the denominator, which must be restricted, because all denominators cannot be equal to zero, other wise it would be undetermined

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4 years ago
Find the area of this shape
ArbitrLikvidat [17]
So you have 2 identical big triangles with the h = 5.75 and b = 4: 

A=(1/2)bh=(1/2)*4*5.75=11.5
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Then you have to smaller identical triangles with the h =2 and b=(4+4-4)/2=2

A=(1/2)*2*2=2
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Add all the calculated areas: 
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The area of the shape is therefore 35 cm^2

Hope that helped. 
8 0
3 years ago
Evaluate the expression. 202 + 6(9 + 3)
andrew11 [14]

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Step-by-step explanation:

5 0
3 years ago
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Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?
Lisa [10]

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

\bf \boxed{6a.1}~\hfill  \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill  \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\\\\\\\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

so let's do 6a1, 6a3 and 6a5.

\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \\\\\\ \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)\div (2\cdot 10)}\implies \stackrel{one}{90\div 20}~\hfill \stackrel{changing}{(9\cdot 70)\div(2\cdot 70)}\implies \stackrel{two}{630\div 140}

3 0
3 years ago
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