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oksian1 [2.3K]
3 years ago
14

Write an expression for "the quotient of 9 and c"

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

9÷c

Quotient is division.

The quotient of 9 and c would be 9 divided by c

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Two neighbors, wilma and betty, each have a swimming pool. both wilma's and betty's pools hold 9900 gallons of water. if wilma's
s2008m [1.1K]
To solve this problem we will start by calculating time needed for each of them to fill the pool.

We have formula:
Volume = rate * time
Or
time = volume / rate

Wilma:
time = 9900 / 900
time = 11h

Betty:
time = 9900 / 500
time = 19.8h

Now we substract these two numbers:
time_difference = 19.8 - 11 = 8.8h

Betty needs 8.8 hours more than Wilma to fill the pool.
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Suppose that the functions p and q are defined as follows.p(x) = -2x + 1q(x)=-x?Find the following.
MariettaO [177]

First let us find

(q\mathrm{}p)(x)\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}

Now let;s solve the second part

\begin{gathered} (p\mathrm{}q)(x)=p(q(x)) \\ =p(-x^2) \\ =-2(-x^2)+1 \\ =2x^2+1 \\ So\text{ (p.q)(5) will be } \\ (p\mathrm{}q)(5)=2(5)^2+1 \\ =51 \end{gathered}

6 0
1 year ago
How do properties of integer exponents help you write equivalent expressions
olga55 [171]

When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.

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Audrey is buying a nee car for $32,998. She plans to make a down payment of $4,200. If she's to make a monthly payments of $525
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4 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
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