Answer:
The solution is: 
Step-by-step explanation:
The Gauss-Jordan elimination method is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.
We have the following system:



This system has the following augmented matrix:
To make the reductions easier, i am going to swap the first two lines. So

Now the matrix is:
![\left[\begin{array}{ccc}1&-2&1|-3\\2&-1&3|-10\\1&-5&2| -7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%261%7C-3%5C%5C2%26-1%263%7C-10%5C%5C1%26-5%262%7C%20-7%5Cend%7Barray%7D%5Cright%5D)
Now we reduce the first row, doing the following operations


So, the matrix is:
![\left[\begin{array}{ccc}1&-2&1|-3\\0&3&1|-4\\0&-3&1| -4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%261%7C-3%5C%5C0%263%261%7C-4%5C%5C0%26-3%261%7C%20-4%5Cend%7Barray%7D%5Cright%5D)
Now we divide L2 by 3

So we have
![\left[\begin{array}{ccc}1&-2&1|-3\\0&1&\frac{1}{3}|\frac{-4}{3}\\0&-3&1| -4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%261%7C-3%5C%5C0%261%26%5Cfrac%7B1%7D%7B3%7D%7C%5Cfrac%7B-4%7D%7B3%7D%5C%5C0%26-3%261%7C%20-4%5Cend%7Barray%7D%5Cright%5D)
Now we have:

So, now we have our row reduced matrix:
![\left[\begin{array}{ccc}1&-2&1|-3\\0&1&\frac{1}{3}|\frac{-4}{3}\\0&0&2| -8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%261%7C-3%5C%5C0%261%26%5Cfrac%7B1%7D%7B3%7D%7C%5Cfrac%7B-4%7D%7B3%7D%5C%5C0%260%262%7C%20-8%5Cend%7Barray%7D%5Cright%5D)
We start from the bottom line, where we have:



At second line:



At the first line



The solution is: 
2 is a factor of 20 and not a multiple of 5
35262 Is the answer just multiply 54 x65 and get the answer then multiply the answer by 3
Answer:
4096
Step-by-step explanation:
The absolute value functions that contains the points are:
- f(x) = |x| + 2
- f(x) = |-x| + 2
<h3>Which could be the function represented by this graph?</h3>
Here we have the points (-3, 5), (0, 2), and (3, 5). We want to see which ones of the given functions have that points.
To check that, we need to evaluate the functions in the first value of each point and see if the outcome is the second value of the correspondent point.
For example, for the first equation:
- f(-3) = |-3| + 2 = 5 so it has the point (-3, 5)
- f(0) = |0| + 2 = 2 so it has the point (0, 2)
- f(3) = |3| + 2 = 5 so it has the point (3, 5).
The other option that also contains these 3 points is:
f(x) = |-x| + 2
- f(-3) = |3| + 2 = 5 so it has the point (-3, 5)
- f(0) = |-0| + 2 = 2 so it has the point (0, 2)
- f(3) = |-3| + 2 = 5 so it has the point (3, 5).
And all the other options can be trivially discarded (by evaluating them).
So the two correct options are:
- f(x) = |x| + 2
- f(x) = |-x| + 2
If you want to learn more about absolute value functions:
brainly.com/question/3381225
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