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3 years ago

I am confused on how to do this? please help!

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

You would take random numbers preferable smaller ones such as -1,0,1,2
You would put those in the place of x
Then you would square the value of x. After that you subtract 4. Whatever you come out with is your y value. Then you put the x value on the x axis and from that point count up or down to the number you need on the y axis. Together that would be your point

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Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

6 0

3 years ago

I need help it’s due soon and i need help please also i solved one but i need three solved thanksssss

mel-nik [20]

Answer:

6) b = -13.55

8) p = -1

9) x = 7

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Step-by-step explanation:

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