267 moles of NADH are produced by the Citric Acid Cycle (CAC). How many moles of glucose needed to be broken down during glycoly
1 answer:
Answer:
45 moles
Explanation:
From glycolysis, 1 mole of glucose gives 2 moles of pyruvate which undergoes citric acid cycle.
1 mole of pyruvate undergoes citric acid cycle (After conversion to acetyl-CoA) gives 3 moles of NADH.
Also,
2 moles of pyruvate undergoes citric acid cycle (After conversion to acetyl-CoA) gives 6 moles of NADH.
Thus,
6 moles of NADH are produced from 2 moles of pyruvate or 1 mole of glucose.
1 mole of NADH is produced from 1/6 mole of glucose
267 moles of NADH are produced from moles of glucose.
<u>Thus, moles of glucose needed to be broken ≅ 45 moles</u>
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<h2>Hello!</h2>
The answer is:
There are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
The dinitrogen pentoxide, or nitrogen pentoxide, is a rare salt that consists of anion and cations, and it's an important compound when preparing some kinds of explosives.
So, to answer the question, first, need to look for the molecular formula of the dinitrogen pentoxide, then, use it to calculate the mass in gram of 6.78 moles of the same compound.
The dinitrogen pentoxide formula is:
Where, the molar mass of each element are:
Calculating the molar mass of the compound, we have:
Now, calculating what is the mass of 6.78 of , we have:
So, there are 732.24 grams of Dinitrogen Pentoxide in 6.78 moles of the same compound.
Have a nice day!