The original question is to find the pH and the pOH of 0.023 M of perchloric acid.
Answer:
pH = 1.638
pOH = 12.362
Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638
2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362
Hope this helps :)
I think the answer is a pure substance
Answer : The partial pressure of the
in the tank in psia is, 32.6 psia.
Explanation :
As we are given 75 %
and 25 %
in terms of volume.
First we have to calculate the moles of
and
.


Now we have to calculate the mole fraction of
.


Now we have to calculate the partial pressure of the
gas.


conversion used : (1 Kpa = 0.145 psia)
Therefore, the partial pressure of the
in the tank in psia is, 32.6 psia.
When a crop of wheat grows, new organic matter is created by the process of photosynthesis, which converts light energy into energy stored in chemical bonds within plant tissue. ... New compounds and structures are synthesized, cells divide, and the plant grows in size over time
thanks
cbuck763
The response would become spontaneous if the value of ΔG° was negative.
According to the estimated value of ΔG°, it is shown that ΔG° value decreases as temperature value increases. The value shifts from being more favorable to being less favorable. It would appear that the value of ΔG° would be negative at a specific temperature, causing the reaction to occur spontaneously.
The reaction is in an equilibrium state if ΔG = 0. If ΔG < 0, the reaction is spontaneous in the direction written. The relationship between terms from the equilibrium is paralleled by the relevance of the sign of a change in the Gibbs free energy.
Learn more about ΔG° here:
brainly.com/question/14512088
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