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Sedaia [141]
3 years ago
8

Contrast the structure of table salt and table sugar

Chemistry
1 answer:
nydimaria [60]3 years ago
4 0
Table salt = ionically bonded molecule, sodium transfers one valence electron to chloride, NaCl

Table sugar = covalently bonded molecule

Sorry, that’s all I know.
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Explain how boiling and evaporating are alike and how they are differant
julsineya [31]

Answer:

The main difference between evaporation and boiling are : 1. Evaporation takes place at all temperatures, while boiling occurs at a particular temperature. 2. Evaporation takes place from the surface, whereas the entire liquid boils. 3. Evaporation can occur using the internal energy of the system, while boiling requires an external source of heat.

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So I lost my sense of taste yesterday.
Mama L [17]

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I'm unaware of what but maybe hot sauce?

Explanation:

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2 years ago
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Srihari has a torch with him and 2 new batteries. However, the torch requires 3 batteries to work. Is there any way Srihari can
zloy xaker [14]

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go to the store to buy more batteries

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6 0
3 years ago
During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What
kvv77 [185]

Answer:

8.70 liters

Explanation:

  • 3O₂+ 4Al → 2AI₂O₃

First we <u>convert 36.12 g of AI₂O₃ into moles</u>, using its <em>molar mass</em>:

  • 36.12 g ÷ 101.96 g/mol = 0.354 mol AI₂O₃

Then we <u>convert AI₂O₃ moles into O₂ moles</u>, using the stoichiometric coefficients of the reaction:

  • 0.354 mol AI₂O₃ * \frac{3molO_2}{2molAl_2O_3} = 0.531 mol O₂

We can now use the <em>PV=nRT equation</em> to <u>calculate the volume</u>, V:

  • 1.4 atm * V = 0.531 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 280.0 K
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5 0
3 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
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