The question is incomplete. Complete question is attached below
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Answer:
Equilibrium constant (K) is defined as the ratio of concentration of product to concentration of reactant.
For the reaction: 2H2O(g) ↔ 2H2(g) + O2(g)
Equlibrium constant =
![\frac{[H_2]^2[O_2]}{[H_20]^2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_20%5D%5E2%7D%20)
[ ] bracket in above expression indicates concentration.
Answer: increases by
As a chlorine atom becomes a negative ion, the atom "increases by" an electron
Explanation:
Chlorine atom has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5 showing 7 valence electrons in its outermost shell.
Hence, it receives a single electron to achieve a stable octet structure with electronic configuration of
1s2, 2s2 2p6, 3s2 3p6. Therefore, Cl- is a univalent negative ion with 8 valence electrons in its outermost shell. The increase is shown below
Cl + e- --> Cl-
Thus, as a chlorine atom becomes a negative ion, the atom "increases by" an electron
Answer:
382.5J
Explanation:
<em>Use the formula:</em>
E = mcΔθ or Q = mcΔT
m = 100g
c = 0.45 J/g°C
ΔT or Δθ = 110 - 25 = 85°
<em>Sub in the values:</em>
E = 100 × 0.45 × 85
= 382.5J
I believe it is:
CH4
Ar
Cl2
CH2COOH
I hope this helps :)