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Vera_Pavlovna [14]
3 years ago
11

PLEASE HELP FOR BRAINLIEST ANSWER!

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0
<span>To which set of numbers does −1.2 belong? </span>D.) rational numbers
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When graphing (3,0) on a coordinate plane, you move 3 units along the
mr Goodwill [35]

Answer:

x-axis

Step-by-step explanation:

When graphing (3, 0) on a coordinate plane, you move 3 units to the right of the origin. This means you are moving along the x-axis.

3 0
3 years ago
Brandi solved 16 / 5 by using a related multiplication expression. What multiplication expression did she is?
klemol [59]

The given question is wrong.

Question:

Brandi solved \frac{1}{6}\div 5 by using a related multiplication expression. What multiplication expression did she is?

Answer:

The related multiplication expression is  $\frac{1}{6}\times \frac{1}{5}.

Solution:

Given expression is \frac{1}{6}\div 5.

We can write 5 as a fraction with denominator 1.

$ \frac{1}{6}\div5=\frac{1}{6}\div \frac{5}{1}

Using the fraction rule  $\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c},

$\frac{1}{6}\div \frac{5}{1}=\frac{1}{6}\times \frac{1}{5}

Now multiply the fractions using the rule $\frac{a}{b}\times \frac{d}{c}=\frac{a\times d}{b\times c},

$\frac{1}{6}\times \frac{1}{5}=\frac{1\times1}{6\times5}

Let us multiply the numbers in the numerator and denominator separately, we get

$\frac{1\times1}{6\times5}=\frac{1}{30}

Hence the related multiplication expression is  $\frac{1}{6}\times \frac{1}{5}.

8 0
3 years ago
How do i solve for the x-intrcepts for 4x^2-3y^2+2xy-12=0
xeze [42]
Put it in slope intercept form and plot the y-axis then plot each of the slopes finding the x-intercept
4 0
3 years ago
What is the product?<br> (7x2y^3)(3x^5=y^8)
spin [16.1K]

Answer:

is the equal sign supposed to be there? if it wasnt then answer would be 42x^6y^11

Step-by-step explanation:

5 0
3 years ago
Simplify the following rational expression.
Jet001 [13]

9514 1404 393

Answer:

  (x-8)/(4x-4)  x ≠ 1 or 8

Step-by-step explanation:

Common factors can be cancelled, but cannot be ignored when it comes to determining where the function is undefined.

  \dfrac{x^2-16x+64}{4x^2-36x+32}=\dfrac{(x-8)^2}{4(x-8)(x-1)}=\boxed{\dfrac{x-8}{4x-4}}

The function is undefined for x=1 and x=8, the values of x that make the original denominator zero.

8 0
3 years ago
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