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nikdorinn [45]
3 years ago
9

Find the circumference and the area of a circle with diameter 2 m .

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:6.28m

Step-by-step explanation:

Schach [20]3 years ago
6 0

Answer:

The answer to your question is Circumference = 12.56 m, Area = 3.14 m²

Step-by-step explanation:

Data

Circumference = ?

Area = ?

diameter = 2 m

Process

1.- Calculate the radius

radius = diameter / 2

-Substitution

radius = 2/2

-result

radius = 1 m

2.- Calculate the circumference

Circumference = 2πr

π = 3.14

Circumference = 2(3.14)(2)

                         = 12.56 m

3.- Calculate the area of the circle

Area = πr²

-Substitution

Area = (3.14)(1)²

-Simplification

Area = (3.14)(1)

-Result

Area = 3.14 m²

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xenn [34]

Answer:

A = 28

B = 87

Step-by-step explanation:

18 + 10 = 28

103 -16 = 87

4 0
3 years ago
Help me pls i dont understand math
e-lub [12.9K]

Answer:

c = -6

Step-by-step explanation:

Let us solve your equation step-by-step, which is this: c /−3  + 5 = 7

The first step is to simplify both sides of the equation: −1 /3 c + 5 = 7

Then, subtract 5 from both sides: -1/3c + 5 - 5 = 7 - 5 ---> -1/3c = 2

Multiply both sides by -3/1 making it equal to: c = -6.

4 0
3 years ago
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

4 0
3 years ago
FIND THE CORRECT PRIME FACTORIZATION OF 20/50, AN THEN REDUCE THE FRACTION TO LOWEST TERMS.
lara [203]
It is B. <span>because</span> <span>it</span> the lowest term and if we multiply it equal to 2*2*5/2*5*= 4*5/10*5= 20/50
6 0
3 years ago
What is the reduced answer to 4/9 multiples by 4/5 equal
deff fn [24]
First, we know that when multiplying fractions, we multiply both the numerator and denominator.

so, in 4/9 • 4/5,
4•4 = 16, and
9•5 = 45

so, 4/9 • 4/5 = 16/45.
now, we’ll look for the Least Common Factor

factors are numbers that you can multiply together to = another number.
the LEAST common Factor is the # that is smallest that you can divide both numbers by, in an equation and get a whole number.

for instance, 3•3 and 1•9 are the only ways to get 9, so, the factors are 1, 3, 9

let’s look for the LCF in 16 and 45. -
if we find the ways to get 16, we have:
1•16, 2•8, and 4•4
so, the factors are 1, 2, 4, 8, and 16.
this is called FACTORING :)

the ways to get 45 are...
1•45, 3•15, and 5•9, so the FACTORS are
1, 3, 5, 9, 15, & 45.
- compare the factors of 16 & 45,
none of them are the same besides 1, and we know that dividing these numbers by 1 will not do anything.

because of this, we can not reduce 16/45, so the reduced answer to 4/9 • 4/5 = 16/45
4 0
3 years ago
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