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slamgirl [31]
3 years ago
10

Find the surface area of the triangular prism.

Mathematics
2 answers:
lbvjy [14]3 years ago
5 0
I’m pretty sure it is 406.56 but I’m not sure I just wanted to let you know :)
Ivahew [28]3 years ago
3 0

I think it's 462.99, rounded it's 463

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What is the height of the prism? 7 cm 14 cm 21 cm 30 cm
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Answer: 61740

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3 years ago
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Find the volume of the rectangular prism. Express your answer as a simplified mixed number.
OverLord2011 [107]

Answer:

Volume = = 138⁶/32 cubic meters

Step-by-step explanation:

Given:

Length = 8⅜ m

Width = 2 m

Height = 8¼ m

Required:

Volume as a mixed number

Solution:

Volume of rectangular prism = L*W*H

Plug in the values

V = 8⅜ × 2 × 8¼

Change to improper fraction

V = 67/8 × 2 × 33/4

= (67 × 2 × 33)/(8 × 4)

= 4,422/32

= 138⁶/32 m³

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3 years ago
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7 0
2 years ago
Using the Rational Root Theorem, what are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x – 12?
igomit [66]

Answer:

Option 1 is correct.

Step-by-step explanation:

The given polynomial is

f(x)=20x^4+x^3+8x^2+x-12

we have to find  all the rational roots of the polynomial f(x)

The Rational Root Theorem states that the all possible roots of a polynomial are in the form of a rational number i.e in the form of \frac{p}{q}

where p is a factor of constant term and q is the factor of coefficient of leading term.

In the given polynomial the constant is -12 and the leading coefficient is 20.

\text{All possible factor of -12 are }\pm1,\pm2, \pm3, \pm4,\pm6,\pm12

\text{All possible factor of 20 are }\pm1,\pm2,\pm4,\pm5,\pm10,\pm20

So, the all possible rational roots of the given polynomial are,

\pm1,\pm2, \pm3, \pm4,\pm6,\pm12,\pm\frac{1}{2},\pm\frac{3}{2},\pm\frac{1}{4},\pm\frac{3}{4},\pm\frac{1}{10},\pm\frac{1}{5},\pm\frac{3}{5},\pm\frac{3}{10},\pm\frac{2}{5},\pm\frac{6}{5},\pm\frac{1}{20},\pm\frac{3}{20},\pm\frac{4}{5},\pm\frac{12}{5}

Now, the rational roots of polynomial satisfy the given polynomial

f(-\frac{4}{5})=20(-\frac{4}{5})^4+(-\frac{4}{5})^3+8(-\frac{4}{5})^2-\frac{4}{5}-12=\frac{256}{625}\times 20-\frac{64}{125}+\frac{128}{125}-\frac{4}{5}-12

=\frac{1024}{125}-\frac{64}{125}+\frac{128}{25}-\frac{4}{5}-12

=\frac{960}{125}+\frac{128}{25}-\frac{4}{5}-12=12-12=0

Hence, rational root.

f(\frac{3}{4})=20(\frac{3}{4})^4+(\frac{3}{4})^3+8(\frac{3}{4})^2+\frac{3}{4}-12=\frac{405}{64}+\frac{27}{64}+\frac{9}{2}+\frac{3}{4}-12=0

rational root

f(1)=20(1)^4+(1)^3+8(1)^2+1-12=20+1+8-11=18\neq 0

not a rational root.

hence, option 1 is correct

8 0
3 years ago
Read 2 more answers
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