If the dept in feet is ?, 18, ? 42 and the dept in fathoms is 1, ?, 4, ?.

A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as

Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that $p = 0.17$

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891$

0.3891 = 38.91% probability that only one is a second

7 0

4 years ago

Needs answers Will mark brainliest

Elden [556K]

QUESTION 1:

Required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

QUESTION 2:

Required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Step-by-step explanation:

Question 1:

if m<1 =105°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <1 is angle 5 So, m<5 = 105°

The vertical angles are also equal. so, vertical angle of <1 is <4. So, m<4 = 105°

Vertical angles of m<5 is m<8 so, m<8=105°

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

105+m<2=180

m<2=75°

Same goes for m<3 and m<4 so, m<3 = 75°

m<5 and m<6 so, m<6 = 75°

m<7 and m<8 so, m<7= 75°

So, required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

Question No 2

if m<3=80°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <3 is angle 7 So, m<7 = 80°

The vertical angles are also equal. so, vertical angle of <3 is <2. So, m<2 = 80°

The Vertical angle of <7 is <6 so, m<6= 80°.

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

m<1+80=180

m<1=100°

Same goes for m<3 and m<4 so, m<4 = 100°

m<5 and m<6 so, m<5 = 100°

m<7 and m<8 so, m<8= 100°

So, required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Keywords: Traversal of parallel lines

Learn more about traversal of parallel lines at:

#learnwithBrainly

3 0

4 years ago

In AABC, AC - BC. The length of AC is three times the length of AB. Find

Arlecino [84]

Answer:

i don't undertsand this question

5 0

3 years ago

PLEASE HELP!

spin [16.1K]

Two-third of the jar is filled with flower
Hope this helped

4 0

3 years ago

If f(n)= n²-n, then f(-4) is O-20 12 -12 20

Harman [31]

Answer:

20

Step-by-step explanation:

Plug in -4 for n:

(-4)^2 - (-4) = 16 + 4 = 20

3 0

2 years ago