Answer:
A^k/b^k
Step-by-step explanation:
A/b^k=a^k/b^k
Well if the straight line is equal to 1 then your answer is 2/3 but if the straight line is not equal to 1 you need to know what it is equal to or you could use the equation y = (2/3)x
"x" would be the length of the straight line and "y" would be two-thirds of it
Linear means the highest exponent on the placholder is 1
it is also just a straight line
y=|x| is like y=(√x)², it is 2 straight lines
B. y=x², exponent is 2 so no
C. y=-3x³, exponent is 3, so no
D. y=1/4x, yep
D is the answer
Answer:
1) +80
2) -1520
Step-by-step explanation:
Positive Signed numbers are used in real world situations to indicate the increase. Examples include; increase in weight, deposit of money into an account, increase in income, profit, height above sea level, etc. They are all represented by positive signed numbers.
Whereas, negative signed numbers show decrease. Examples include; loss of weight, withdrawal of money from an account, loans, liabilities, losses, temperature below zero degrees, height below sea level.
1) We are told that Reuben received 80 dollars. Thus, it means he received an increase in the amount of money he already had. Thus, the signed number will be +80.
2) We are told that A car corporation produced 1520 fewer cars this month than last.
Thus, the signed number will be negative since there is a decrease in number of cars.
Thus, signed number = -1520
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
To learn more about students visit:
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