Answer:
Ok ill help
Step-by-step explanation:
Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>
5x/6-5/12, x-1/12, x+1/12
Step-by-step explanation:
Answer:
Step-by-step explanation:
Yikes. This is quite a doozy, so pay attention. We will begin by factoring by grouping. Group the first 2 terms together into a set of parenthesis, and likewise with the last 2 terms:
and factor out what's common in each set of parenthesis:
. Now you can what's common is the (d + 3), so factor that out now:
BUT in that second set of parenthesis, we can still find things common in both terms, so we continue to factor that set of parenthesis, carrying with us the (d + 3):
BUT that second set of parenthesis is the difference of perfect squares, so we continue factoring, carrying with us all the other stuff we have already factored:
. That's completely factored, but it's not completely simplified. Notice we have 2 terms that are identical: (d + 3):
is the completely factored and simplified answer, choice 3)
