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3 years ago

How do you put 5.96 as a fraction

Mathematics

1 answer:

Genrish500 [490]3 years ago

6 0

5.96 into a fraction = 596/100 or 149.25

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On Monday, 30% of the 900 students at Maple Middle school walk to school. Complete the double numberline model. How many student

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3 years ago

RS = 4x – 9, ST = 19, RT = 80 – 14 Equation: 82 – 14 RS RT

algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

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4 years ago

What kind of property is this problem 3x(k+4)=3xk+12

ser-zykov [4K]

If i'm not wrong its distributing property of addition.

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3 years ago

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

4 0

3 years ago

PLEASE HELP! Which ordered pairs are solutions to the inequality y-4x (greater than or equal to) -5? Select each correct answer

Wittaler [7]

(-2, 1), (-4, 2) and (1, -1) are solutions to given inequality y-4x (greater than or equal to) -5

Solution:

Given, inequality is y – 4x ≥ - 5

We have to find the correct answers from given options

We have to check option by option.

Now, (-2, 1) ⇒ 1 – 4(-2) ≥ - 5 ⇒ 1 + 8 ≥ -5 ⇒ 9 ≥ -5 ⇒ correct answer.

Now, (-4, 2) ⇒ 2 – 4(-4) ≥ -5 ⇒ 2 + 16 ≥ - 5 ⇒ 18 ≥ - 5 ⇒ correct answer

Now, (1, -1) ⇒ -1 – 4(1) ≥ - 5 ⇒ -1 – 4 ≥ - 5 ⇒ -5 ≥ -5 ⇒ correct answer

Now, (4, 0) ⇒ 0 – 4(4) ≥ - 5 ⇒ -16 ≥ -5 ⇒ wrong answer

Now, (5, -2) ⇒ -2 – 4(5) ≥ - 5 ⇒ -2 – 20 ≥ -5 ⇒ -22 ≥ -5 ⇒ wrong answer

Hence, (-2, 1), (-4, 2) and (1, -1) are solutions to given inequality.

8 0

3 years ago