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3 years ago

A bookstore is hosts the stars from the Harry Potter

Mathematics

2 answers:

Maurinko [17]3 years ago

4 0

Answer : The number of fans or people in the building to meet the stars can be, 5985

Step-by-step explanation :

Given:

Area of the store = 15000 ft²

Area of the stage = 36 ft²

Area of the each person = 2.5 ft²

First we have to calculate the left area for the people.

Left area for the people = Area of the store - Area of the stage

Left area for the people = 15000 ft² - 36 ft²

Left area for the people = 14964 ft²

Now we have to calculate the number of fans or people can be in the building to meet the stars.

Number of fans to meet the stars = $\frac{\text{Left area for the people}}{\text{Area of the each person}}$

Number of fans to meet the stars = $\frac{14964ft^2}{2.5ft^2}$

Number of fans to meet the stars = 5985

Therefore, the number of fans or people in the building to meet the stars can be, 5985

shepuryov [24]3 years ago

3 0

Answer:

5985 can fit in the room!

Step-by-step explanation:

1) 150 * 100 = 15000

2) 6 * 6 = 36

3) 15000 - 36 = 14964

4) 14964 / 2.5 = 5985.6

5) But you can't fit almost half a person inside or create another whole person soo you round down to 5985

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A street light is at the top of a 11 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 7 ft/sec along a s

zheka24 [161]

Answer:

The answer is 8.5 Ft/Sec.

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

Step-by-step explanation:

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

The solution and explanation is attached.

Download pdf

7 0

3 years ago

What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?

xxMikexx [17]

We have been given an equation of hyperbola $\frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1$ . We are asked to find the center of hyperbola.

We know that standard equation of a vertical hyperbola is in form $\frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1$ , where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

$\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1$

Now we can see that value of k is $-3$ . Therefore, the vertex of given hyperbola will be at point $(6,-3)$ and option D is the correct choice.