Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the

Question

4 years ago

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Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the

larger ball than the smaller ball? Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.
Enter your answer in the box.

Mathematics

2 answers:

GaryK [48] · Answer 1 · 2021-12-17T09:32:10+03:00

GaryK [48]4 years ago

7 0

Answer: 17.182.08, I took the test and got a 100%, YOU will too!!

EVERYONE HAVE A GREAT DAY!!! Hope I put a smile on your face :)))

Step-by-step explanation:

BlackZzzverrR [31] · Answer 2 · 2021-12-17T07:29:35+03:00

The answer is 17,182.08 cm³

To calculate this we need to calculate the volume of each ball V2 - V1 = ?
The volume of a sphere with radius r is:
V = 4/3 π r³

Ball 1:
r1 = 18 cm
V1 = 4/3 * 3.14 * 18³
V1 = 24,416.64 cm³

Ball 2:
r2 = 12 cm
V2 = 4/3 * 3.14 * 12³
V2 = 7,234.56 cm³

<span>How much more water is in the larger balloon than in the smaller balloon:
V2 - V1 = </span>24,416.64 cm³ - 7234.56 cm³
= 17,182.08 cm³