<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
The shape moved over 10 and up three. Is this what you’re looking for?
Im not sure but it should be 8.5
Answer:
x=4,y=−2
Step-by-step explanation:
1 Solve for x in -2y+x=8
x=8+2y
2 Substitute x=8+2y into 3y+2x=2
7y+16=2
3 Solve for y in 7y+16=2
y=-2
4 Substitute y=-2 into x=8+2y
x=4
5 Therefore,
x=4
y=−2
