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BartSMP [9]
3 years ago
11

What is 6.7 times 10 to the seventh power?

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0

Answer:

6.7 * (10^7) = 67 000 000

dalvyx [7]3 years ago
6 0

6.7 * 10^7

10^7 = 10,000,000 * 6.7 = 67,000,000

You might be interested in
Show work / explain it ​
aivan3 [116]
Answer:
X 1 = -4,X 2 =12

EXPLANATION:

Determine the defined range
X+6/x=6/x-8,x#0,x#8

Simplify the equation using cross-multiplication
(X+6) x (x-8)=6x

Move variable to the left-hand side and change its sign
(X-6)x(x-8)-6x=0

Multiply the parentheses
X^2-8x+6x-48-6x=0

Since two opposites add up to zero, remove them from the expression
X^2-8x-48=0

Write -8x as a difference
X^2+4x-12x-48=0

Factor out x from the expression
Xx(x+4)-12x-48=0

Factor out -12 from the expression
Xx(x+4)-12(x+4)=0

Factor out from the expression
(x+4)x(x-12)=0

When the product of factors equals 0, at least one factor is 0
x+4=0
x-12=0

Solve the equation for x
X=-4
X-12=0
X=-4,x#0,x#8

Check if the solution is in the defined range
X=-4
x=12

The equation has 2 solutions

X 1 = -4,X 2 =12

Hope this helps


3 0
3 years ago
Four friends bought tickets to the school play if it cost them a total of $28 find how much each friend paid?
galina1969 [7]

Answer:

28:4=7

Pls mark as brainliest

8 0
3 years ago
HELP I NEED HELP ASAP
victus00 [196]

Answer: (5, -2)

Step-by-step explanation:

y= x-7\\2x+y=8

Substitute x-7 for y in 2nd equation

2x+ x-7 =8\\3x-7=8\\3x = 15\\x=5

Solve for y

y=5-7\\y=-2

8 0
3 years ago
HELP MEHHHHHHHH
yKpoI14uk [10]

Answer:

The correct option is;

B. 50 km/h

Step-by-step explanation:

The information given in the question are;

The distance between the two cities = 140 km

The direction of motion of the first car = From A to B (left)

The direction of motion of the second car = From B to A

The time after which both cars meet = 1 hour

The time duration it takes after both cars meet for the second car to reach A = 35 minutes

The total time taken by the second car from city B to city A = The time it takes to meet the first car + The time it takes after meeting the first car to reach city A

∴ The total time taken by the second car from city B to city A = 1 hour + 35 minutes = 60 minutes + 35 minutes = 95 minutes

95 minutes = 95/60 hours = 1⁷/₁₂ hours =  1.58\bar 3 hours

The speed of the second car = Distance/Time = 140 km/(1.58\bar 3 hours) ≈ 88.42 km/h

Therefore, let the distance from A of the point the first car meet the second car = x

Therefore, we have;

The distance from B of the point both cars meet  = (140 - x) km

Given that both cars meet after one hour, we have;

The distance travelled by the second car coming from city B, after one hour = (140 - x) km = Speed of the second car × 1 hour

88.42 km/h × 1 hour = 88.42 km = (140 - x) km

x = 140 - 88.42 ≈ 51.58 km

The distance from A of the point the first car meet the second car = x = 51.58 km

The speed of car A = (The distance from A of the point the first car meet the second car)/(Time it takes both cars to meet)

∴ The speed of the first car = 51.58 km/(1 hour)

The speed of the first car = 51.58 km/h ≈ 50 km/h (Rounding up to the nearest 10th).

5 0
2 years ago
The x-y is the answer can someone please explain to me how to do
guapka [62]

Answer:

Step-by-step explanation:

\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y})-(\sqrt{x-y})*(\sqrt{x+y}-\sqrt{x-y})}{(\sqrt{x+y}-\sqrt{x-y})*(\sqrt{x+y}+\sqrt{x-y})}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y}-\sqrt{x+y}+\sqrt{x-y})}{(\sqrt{x+y})^2-(\sqrt{x-y)^{2}}}\\\\=\frac{\sqrt{x-y}*2\sqrt{x-y}}{x+y-x+y}\\\\=2*\frac{x-y}{2y}=\frac{x-y}{y}\\\\(\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}})*y=\frac{x-y}{y}*y\\\\=x-y

4 0
3 years ago
Read 2 more answers
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