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tresset_1 [31]
3 years ago
11

Tides are mostly caused by

Chemistry
1 answer:
shutvik [7]3 years ago
5 0
The force of the Moon’s gravity
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Do you think it was fair to name the experiment after Rutherford while ignoring the other two scientists?
Arturiano [62]
No, i think that they should have hyphenated it or something. Everyone should get credit for their own work. (lol says me, using brainly)
8 0
4 years ago
If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? (Assume the density of wa
11Alexandr11 [23.1K]

Answer:

0.425 L  

Explanation:

Given the information from the question.  We know that the water heat evaporation is given by 2261 KJ/kg. Therefore, for each Kg of vapor, 2261 is required.

To calculate the amount of water evaporated by 960 KJ is as follows  

= (1/2260)*960 =0.425 Kg

In other words, 0.425 of water is evaporated by 960 KJ.  

To calculate the volume of water, we have mass and density. Therefore, Volume = Mass/Density = 425g/1g/ml = 0.425 L.

Therefore, water evaporated is 0.425 L  

5 0
4 years ago
Compared to a calcium atom, the calcium ion Ca2+ has
Tanzania [10]
The answer is definitely 4. It has fewer electrons. This is because, whenever the electrons are few, they are positive. Positive electrons are anions, while the negative ones are cations. Hope i helped. Have a nice day.
8 0
4 years ago
Read 2 more answers
Consider the market for paper. Let market demand be given by inverse demand function P d (Q) = 60 − Q, where Q is tons of paper
MakcuM [25]

Answer:

See explaination

Explanation:

Demand for paper is given below:

P(Q)=60-Q,

Number of paper mills=20

The cost curve for firm is given below:

C(Q)=10Q2

The external cost in terms of pollution down river by production of paper is given below:

EC(Q)=10Q2

a. The optimal level of paper production by market can be calcuated by equating MC=P

20Q=P

Q=P/20

b. The optimal level of paper production by market can be calcuated by equating MC=P.

MC=20Q

60-(20Q)=20Q

Q=60/40

Q=1.5

Total quanity by 20 firms will be 1.5*20=30

c. The socially efficient level of paper output is calcuated below:

MC+EC'=20Q+20Q

60-(20Q)=40Q

Q=60/60

Q=1

Total quanity by 20 firms will be 1*20=20

The price will be P=60-20=40

d, The deadweight loss occurs as market price increases and quantity decreases due to the external cost . The deadweight loss is calcuated below:

DWL=(1/2)*change in price* change in quantity

=(1/2)*10*10=50

e. 20 firms merged into one firm to make monopoly firm. The cost function for the monopoly is given below:

Cm(Q)=20*10(Q/20)2

The marginal cost for the monopoly firm will be

MCm=Q

The marginal revenue for the firm is 60-2Q

For optimal output MR is equated to MC

60-2Q=Q

Q=20

P=40.

The monopoly outcome is below the perfect competition outcome and price is higher in comparison to perfect competition. The monopoly outcome is same as socially efficient outcome.

The total surplus for this outcome is sum of consumer surplus and producer surplus and subtraction of external cost

TS=CS+PS-EC

=(1/2)*20*20+(1/2)*40*20-10(20)2

=600-4000=-3400

Due to the external effects the total surplus to the society is negative. In perfect competition this effect is not considered and output produced is high therefore, the external cost will be higher with higher output leading to higher negative social surplus. Generally the monopoly outcome reduces the total social surplus but in case of externality, the monopoly total surplus is higher than the perfect competition.

3 0
3 years ago
What is the pH of a 900 mL solution containing 3.40 grams of hydrocyanic acid
Allushta [10]

Answer:

pH = 5.05

Explanation:

pH is derived from the concentration of hydronium ions in a solution. Hydrocyanic acid is HCN.

First, we shall figure out the moles of HCN:

\frac{3.4g}{27.03g/mol}  = 0.125786

If HCN was a strong acid:

HCN has a 1:1 ratio of H+ ions, the moles of H+ is also the same.

To find the molarity, we now divide by Liters. This gets us:

\frac{0.125786 moles}{0.9L} = 0.139762 M

Finally, we plug it into the definition of pH:

pH = -log[H^{+} ]

pH = -log(0.139762)

pH = 0.855

However, since HCN is a weak acid, it only partially dissociates. The K_a of HCN is 6.2 * 10^{-10}.

K_a = \frac{[H^+][A^-]}{[HA]}

We can use an ice table to determine that when x = H+,

K_a = \frac{x^2}{0.125786-x}

[H^+] = 8.83*10^{-6}

pH = -log[H^{+} ]

pH = -log(8.83 * 10^{-6} )

pH = 5.05

7 0
4 years ago
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