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Ugo [173]
3 years ago
7

When determining the density of a pure liquid or solution the temperature of the sample must be measured what is the density of

a liquid sample depend on the temperature
Chemistry
1 answer:
Whitepunk [10]3 years ago
3 0
Idk I just need points sorry man
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The stomach and intestines are organs of the body system which _______.
yulyashka [42]

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A. Digests food

Explanation:

Look about diggestive process in Google

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3 0
3 years ago
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What element has an atomic mass 4?
Daniel [21]

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

4 0
3 years ago
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You have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g
Leno4ka [110]

If you were to cut the radium  in half and have only 90 g, it will take up 18 cm³.

<h3>What is density?</h3>

The density of an object is the ratio of mass to volume of object.

Density = mass/volume

volume = mass/density

at a constant density, the volume of an object is proportional to its mass.

From the question, you have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g, the new mass will take the following volume.

180 g = 36 cm³

90 g =  ?

= (90 x 36) / 180

= 18 cm³

Thus, if you were to cut the radium  in half and have only 90 g, it will take up 18 cm³.

Learn more about radium here: brainly.com/question/23781489

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6 0
1 year ago
Give the systematic name for this coordination compound. k3 cr(cn)6
Helen [10]

Potassium hexacyanochromate(III)

A systematic name is a name given in a systematic way to a chemical substance, out of a definite collection.

The systematic name for the coordination compound k3 cr(cn)6 is Potassium hexacyanochromate(III). This compound contains potassium (k3), six cn which is called hexacyano, and cr (chromium).

 






8 0
3 years ago
Complete combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO2 and 12.2 g of H2O. What is the empirical formula for the h
amid [387]

The empirical formula of the hydrocarbon is C_2H_3 if combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO_2 and 12.2 g of H_2O.

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule CH_2O is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of CO_2:

(\frac{12}{44}) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

(\frac{2}{18} × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = \frac{2.3073}{12}  = 0.1923 moles

Hydrogen = \frac{0.2889}{1}= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               \frac{0.1923}{0.1923} : \frac{0.2889}{0.1923}

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is C_2H_3.

Learn  more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

8 0
2 years ago
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